Question

Find the additive inverse each of the following numbers
\[\dfrac{8}{5},\dfrac{6}{10},\dfrac{-3}{8},\dfrac{-16}{3},\dfrac{-4}{1}\]

Answer 1

Hint: In general the additive inverse of any number is that which we add in a given number and get zero as answer. To find the additive inverse of a fraction, we simply change the sign of that number.

Complete step by step answer:
(1) In case of \[\dfrac{8}{5}\] , the additive inverse in the negative of \[\dfrac{8}{5}\]
i.e. \[\dfrac{-8}{5}\]
(2) In case of \[\dfrac{6}{10}\], the additive inverse in the negative of \[\dfrac{6}{10}\]
i.e. \[\dfrac{-6}{10}\]

(3) In case of \[\dfrac{-3}{8}\] , the additive inverse is the negative of \[\dfrac{-3}{8}\]
i.e. \[-\left( \dfrac{-3}{8} \right)=\dfrac{3}{8}\]
.(4) In case of \[\dfrac{-16}{3}\], additive inverse is the negative of \[\dfrac{-16}{3}\]
i.e. \[-\left( \dfrac{-16}{3} \right)=\dfrac{16}{3}\]
(5) In case of \[\dfrac{-4}{1}\], additive inverse of \[\dfrac{-4}{1}\] is negative of that number
i.e. \[-\left( \dfrac{-4}{1} \right)\Rightarrow \dfrac{4}{1}\]

Note: In fraction we only change the sign of either numerator or denominator because if we change the sign of both numerator and denominator then the value of the original fraction remains the same.
So we need to remember to find an additive inverse of fraction we only change sign of either numerator or denominator.