Question

Find out the temperature of absolute zero kelvin
A) ${0^ \circ }C$
B) ${100^ \circ }C$
C) ${273^ \circ }C$
D) $- {273^ \circ }C$
E) $- {100^ \circ }C$

Answer 1

Hint: You can easily solve this question by trying to recall the relation between Celsius $\left( {^ \circ C} \right)$ and Kelvin $\left( K \right)$ units of the temperature. Remember that the relation between them is very simple and includes the addition or subtraction of a constant number.

Complete step by step answer:
The temperature in Kelvin $\left( K \right)$ given to us in the question: $0K$
We already know that the relation between Celsius $\left( {^ \circ C} \right)$ and Kelvin $\left( K \right)$ units of the temperature can be given as:
$^ \circ C = K - 273$
Hence, we can see that this is a very simple relation and using this, we can find the answer to the given question as
$ ^ \circ C = K - 273$
$ ^ \circ C = 0 - 273 $
$ ^ \circ C = - {273^ \circ }C $

Hence, the correct answer is option (D).

Additional information:
Absolute zero is the lowest limit of the thermodynamic temperature scale, a state at which the enthalpy and entropy of a cooled ideal gas reach their minimum value, taken as zero kelvins. The fundamental particles of nature have minimum vibrational motion, retaining only quantum mechanical, zero-point energy-induced particle motion. The theoretical temperature is determined by extrapolating the ideal gas law; by international agreement, absolute zero is taken as $ - {273.15^ \circ }$ on the Celsius scale, which equals \[ - {459.67^ \circ }\] on the Fahrenheit scale. The laws of thermodynamics indicate that absolute zero cannot be reached using only thermodynamic means, because the temperature of the substance being cooled approaches the temperature of the cooling agent asymptotically, and a system at absolute zero still possesses quantum mechanical zero-point energy, the energy of its ground state at absolute zero. The kinetic energy of the ground state cannot be removed.

Note:
Common mistakes that students make while solving this question is that instead of subtracting from the Kelvin value, they get confused and add $273$ to the kelvin value and thus tick the wrong option as the answer and lose marks over such a silly mistake.