Find out the moment of inertia of the following structure (written as $PHYSICS$ ) about the axis $AB$ made of thin uniform rods of mass per unit length $\lambda $ .
A. \[13\lambda {l^3}\]
B. $10\lambda {l^3}$
C. $7\lambda {l^3}$
D. $11\lambda {l^3}$
Answer
591.3k+ views
Hint: In this question, use the moment of inertia concept that is product of mass and square of its perpendicular distance from the origin to calculate the moment of inertia of a latter. The total number of letters in “PHYSICS” is $7$. And multiply the moment of inertia by seven to calculate the total moment of inertia.
Complete step by step answer:
In this problem, first we must know about the moment of inertia. As per definition we know that, moment of inertia is a quantity representing the body’s tendency to resist the angular acceleration, which is the sum of the products of the mass of each particle in the body with square of its distance from the axis of rotation moment of inertia is used to calculate the angular momentum and allows us to explain how is the rotation motion change when the distribution of mass change.
As we know that the mathematical expression of the moment of inertia is,
$I = m{r^2}$
Where, $r$ is the perpendicular distance from the origin and $m$ is the mass.
Also, in this question given that mass per unit length is $\lambda $ and the perpendicular distance from the origin is $l$
So, the mass will be,
$m = \lambda \times l$
It is given in the question that each letter is made up of same rod, so the mass of each latter will be $m = \lambda \times l$
Now we will calculate the moment of inertia of letter $P$ by substituting the values in the moment of inertia equation as,
$I = \lambda l \times {l^2}$
$ \Rightarrow I = \lambda {l^3}$
As we know that the total latter in the word PHYSICS is $7$.
Therefore, the total moment of inertia of the word Physics will be $7\lambda {l^3}$
Therefore, option C is correct.
Note:
The given question is based on the length of the rod as the density of the rod is depend on the length, so we have taken the distance based on the center of the rod length, but if the density depend on the volume of the rod then the distance will be taken on the basis on the center of mass.
Complete step by step answer:
In this problem, first we must know about the moment of inertia. As per definition we know that, moment of inertia is a quantity representing the body’s tendency to resist the angular acceleration, which is the sum of the products of the mass of each particle in the body with square of its distance from the axis of rotation moment of inertia is used to calculate the angular momentum and allows us to explain how is the rotation motion change when the distribution of mass change.
As we know that the mathematical expression of the moment of inertia is,
$I = m{r^2}$
Where, $r$ is the perpendicular distance from the origin and $m$ is the mass.
Also, in this question given that mass per unit length is $\lambda $ and the perpendicular distance from the origin is $l$
So, the mass will be,
$m = \lambda \times l$
It is given in the question that each letter is made up of same rod, so the mass of each latter will be $m = \lambda \times l$
Now we will calculate the moment of inertia of letter $P$ by substituting the values in the moment of inertia equation as,
$I = \lambda l \times {l^2}$
$ \Rightarrow I = \lambda {l^3}$
As we know that the total latter in the word PHYSICS is $7$.
Therefore, the total moment of inertia of the word Physics will be $7\lambda {l^3}$
Therefore, option C is correct.
Note:
The given question is based on the length of the rod as the density of the rod is depend on the length, so we have taken the distance based on the center of the rod length, but if the density depend on the volume of the rod then the distance will be taken on the basis on the center of mass.
Recently Updated Pages
The magnetic field in a plane electromagnetic wave class 11 physics CBSE

In a plane electromagnetic wave the electric field class 12 physics CBSE

A plane electromagnetic wave travels in vacuum along class 12 physics CBSE

Basicity of sulphurous acid and sulphuric acid are

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

What are the examples of C3 and C4 plants class 11 biology CBSE

State and prove Bernoullis theorem class 11 physics CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

10 examples of friction in our daily life

A body is said to be in dynamic equilibrium if A When class 11 physics CBSE

