
Find k if 0.7k-1.9=0.3( k+14).
Answer
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Hint: Here the given problem is \[0.7k-1.9=0.3\left( k+14 \right)\].We have to find the value of k. So Moving the k terms to the left hand side and remaining numericals to the right hand side and then performing the mathematical operations we will get the solution.
Complete step-by-step answer:
The given problem is \[0.7k-1.9=0.3\left( k+14 \right)\].
Considering L.H.S as \[0.7k-1.9\] and R.H.S as \[0.3\left( k+14 \right)\]
Now in the R.H.S, 0.3 is multiplied with k and 14. The term now appears as \[0.3k+0.3\times 14\]
Now moving the k terms to the left hand side and remaining numericals to the right hand side. The equation now appears as \[0.7k-0.3k=\left( 0.3\times 14 \right)+1.9\]
Now k is taken as common in the left hand side, the equation now appears as \[k\left( 0.7-0.3 \right)=\left( 0.3\times 14 \right)+1.9\]
The value 0.3 is multiplied with 14 and the value 1.9 is added to the obtained value, the equation now appears as \[0.4k=4.2+1.9\]
Adding all the terms in the right hand side, The equation now appears as \[0.4k=6.1\]
Dividing the value 0.4 on both sides we get the required equation as \[\dfrac{0.4k}{0.4}=\dfrac{6.1}{0.4}\]
In left hand side 0.4 gets cancelled in both numerator and denominator, , the equation now appears as \[k=\dfrac{6.1}{0.4}\]
In right hand side dividing 6.1 with 0.4 we get the value of k as \[k=15.25\]
Therefore the value of k is 15.25.
If we put the value of k in both L.H.S and R.H.S we get both the terms equal.
Hence the value of k is 15.25
Note: This is a direct problem where the value of k can be found by moving the terms from L.H.S to R.H.S and performing mathematical expressions. To check placing the value of k in the above equation gives L.H.S = R.H.S.
Complete step-by-step answer:
The given problem is \[0.7k-1.9=0.3\left( k+14 \right)\].
Considering L.H.S as \[0.7k-1.9\] and R.H.S as \[0.3\left( k+14 \right)\]
Now in the R.H.S, 0.3 is multiplied with k and 14. The term now appears as \[0.3k+0.3\times 14\]
Now moving the k terms to the left hand side and remaining numericals to the right hand side. The equation now appears as \[0.7k-0.3k=\left( 0.3\times 14 \right)+1.9\]
Now k is taken as common in the left hand side, the equation now appears as \[k\left( 0.7-0.3 \right)=\left( 0.3\times 14 \right)+1.9\]
The value 0.3 is multiplied with 14 and the value 1.9 is added to the obtained value, the equation now appears as \[0.4k=4.2+1.9\]
Adding all the terms in the right hand side, The equation now appears as \[0.4k=6.1\]
Dividing the value 0.4 on both sides we get the required equation as \[\dfrac{0.4k}{0.4}=\dfrac{6.1}{0.4}\]
In left hand side 0.4 gets cancelled in both numerator and denominator, , the equation now appears as \[k=\dfrac{6.1}{0.4}\]
In right hand side dividing 6.1 with 0.4 we get the value of k as \[k=15.25\]
Therefore the value of k is 15.25.
If we put the value of k in both L.H.S and R.H.S we get both the terms equal.
Hence the value of k is 15.25
Note: This is a direct problem where the value of k can be found by moving the terms from L.H.S to R.H.S and performing mathematical expressions. To check placing the value of k in the above equation gives L.H.S = R.H.S.
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