Question

How do you find all the factors of $47$ ?

Answer 1

Hint: In this question, we need to find the prime factors of $47$ . Here, we will determine the factors of $47$ , then we will determine the prime factors of $47$ , using the method of prime factorization. The method of prime factorisation should be followed carefully as taught in early stages of mathematics.

Complete step by step solution:
Here, we need to find the prime factors (all factors) of $47$ using prime factorization as it is a prime number.
We know that $47$ is a composite number.
Therefore, the possible factors of $47$ are: $47\times 1$
Prime factorization is a method of finding prime numbers which multiply to make the original number.
A prime number is a natural number greater than $1$ that is not a product of two smaller natural numbers.
In prime factorization, we start dividing the number by the first prime number $2$ and continue to divide by $2$ until we get a decimal or remainder. Then divide by $3,5,7,....$ etc. until we get the remainder $1$ with the factors as prime numbers. Then write the numbers as a product of prime numbers.
Thus, prime factorization of $47$ is,
 $47=1\times 47$
This can be also written in exponential form.
So, all factors of $47$ are: $1$ and $47$ .
So, the correct answer is “ $1$ and $47$ ”.

Note: In this question it is important to note here that a composite number is a positive integer that can be formed by multiplying two smaller positive integers. Equivalently, it is a positive integer that has at least one divisor other than $1$ and itself. However, the prime factorization is also known as prime decomposition. And, the prime factorization of the prime number is the number itself and $1$ . Every other number can be broken down into prime number factors, but the prime numbers are the basic building blocks of all the numbers.