Question

How do you find all the factors of $ 47 $ ?

Answer 1

Hint: In this question, we need to find the prime factors of $ 47 $ . Here, we will determine the factors of $ 47 $ , then we will determine the prime factors of $ 47 $ , using the method of prime factorization. The method of prime factorisation should be followed carefully as taught in early stages of mathematics.

Complete step by step solution:
Here, we need to find the prime factors (all factors) of $ 47 $ using prime factorization as it is a prime number.
We know that $ 47 $ is a composite number.
Therefore, the possible factors of $ 47 $ are: $ 47 \times 1 $
Prime factorization is a method of finding prime numbers which multiply to make the original number.
A prime number is a natural number greater than $ 1 $ that is not a product of two smaller natural numbers.
In prime factorization, we start dividing the number by the first prime number $ 2 $ and continue to divide by $ 2 $ until we get a decimal or remainder. Then divide by $ 3,5,7,.... $ etc. until we get the remainder $ 1 $ with the factors as prime numbers. Then write the numbers as a product of prime numbers.
Thus, prime factorization of $ 47 $ is,
 $ 47 = 1 \times 47 $
This can be also written in exponential form.
So, all factors of $ 47 $ are: $ 1 $ and $ 47 $ .
So, the correct answer is “ $ 1 $ and $ 47 $ ”.

Note: In this question it is important to note here that a composite number is a positive integer that can be formed by multiplying two smaller positive integers. Equivalently, it is a positive integer that has at least one divisor other than $ 1 $ and itself. However, the prime factorization is also known as prime decomposition. And, the prime factorization of the prime number is the number itself and $ 1 $ . Every other number can be broken down into prime number factors, but the prime numbers are the basic building blocks of all the numbers.