
How do you find a one sided limit for an absolute value function?
Answer
546.3k+ views
Hint: A function is expressed in terms of a variable quantity represented by an alphabet, as the value of the variable changes; the value of the function also changes. The values of the variable are called the input or index values. Thus the limit of a function is defined as the value that the function approaches when the input or index value approaches some value. As the input value approaches some specific value from the left or the right side, both these limits are called one-sided limits of the function. Thus, we have to find the left-hand limit and right-hand limit of the absolute value function.
Complete step-by-step answer:
Let an absolute value function be $ \left| {x + 1} \right| $ , the function is changes sign from negative to positive at x=-1, so for finding one-sided limit, its limit is expressed as –
$ \mathop {\lim }\limits_{x \to - 1} \left| {x + 1} \right| $
Left-hand limit –
$
\mathop {\lim }\limits_{x \to - {1^ - }} = - (x + 1) \\
\Rightarrow \mathop {\lim }\limits_{x \to - 1 - h} - x - 1,\,where\,h \to 0 \\
\Rightarrow \mathop {\lim }\limits_{h \to 0} - ( - 1 - h) - 1 \\
\Rightarrow \mathop {\lim }\limits_{x \to - {1^ - }} - x = \mathop {\lim }\limits_{h \to 0} 1 + h - 1 = 0 \\
$
Right-hand limit –
$
\mathop {\lim }\limits_{x \to - {1^ + }} (x + 1) \\
\Rightarrow \mathop {\lim }\limits_{x \to - 1 + h} x + 1,\,where\,h \to 0 \\
\Rightarrow \mathop {\lim }\limits_{h \to 0} - 1 + h + 1 \\
\Rightarrow \mathop {\lim }\limits_{x \to - {1^ + }} = \mathop {\lim }\limits_{h \to 0} h = 0 \\
$
Now, Left-hand limit is equal to the right-hand limit.
This way we find one side limit for an absolute value function.
Note: An absolute value function always gives a non-negative number as the answer, that is, if the input value is a negative number, the absolute value function (also called modulus function) converts it into a positive function while a positive input value remains a positive value. $ \left| x \right| = x $ when x is positive and $ \left| x \right| = - x $ when x is negative; thus an absolute is a piecewise function that is it can be written as two subfunctions, that’s why we can find its one-sided value.
Complete step-by-step answer:
Let an absolute value function be $ \left| {x + 1} \right| $ , the function is changes sign from negative to positive at x=-1, so for finding one-sided limit, its limit is expressed as –
$ \mathop {\lim }\limits_{x \to - 1} \left| {x + 1} \right| $
Left-hand limit –
$
\mathop {\lim }\limits_{x \to - {1^ - }} = - (x + 1) \\
\Rightarrow \mathop {\lim }\limits_{x \to - 1 - h} - x - 1,\,where\,h \to 0 \\
\Rightarrow \mathop {\lim }\limits_{h \to 0} - ( - 1 - h) - 1 \\
\Rightarrow \mathop {\lim }\limits_{x \to - {1^ - }} - x = \mathop {\lim }\limits_{h \to 0} 1 + h - 1 = 0 \\
$
Right-hand limit –
$
\mathop {\lim }\limits_{x \to - {1^ + }} (x + 1) \\
\Rightarrow \mathop {\lim }\limits_{x \to - 1 + h} x + 1,\,where\,h \to 0 \\
\Rightarrow \mathop {\lim }\limits_{h \to 0} - 1 + h + 1 \\
\Rightarrow \mathop {\lim }\limits_{x \to - {1^ + }} = \mathop {\lim }\limits_{h \to 0} h = 0 \\
$
Now, Left-hand limit is equal to the right-hand limit.
This way we find one side limit for an absolute value function.
Note: An absolute value function always gives a non-negative number as the answer, that is, if the input value is a negative number, the absolute value function (also called modulus function) converts it into a positive function while a positive input value remains a positive value. $ \left| x \right| = x $ when x is positive and $ \left| x \right| = - x $ when x is negative; thus an absolute is a piecewise function that is it can be written as two subfunctions, that’s why we can find its one-sided value.
Recently Updated Pages
Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Biology: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 8 Maths: Engaging Questions & Answers for Success

Class 8 Question and Answer - Your Ultimate Solutions Guide

Trending doubts
What is meant by exothermic and endothermic reactions class 11 chemistry CBSE

Which animal has three hearts class 11 biology CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

