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More # Find a number when multiplied by $5$ exceeds itself by $64$ $A)$$14$$B)$$16$$C)$$8$$D)$$18 Answer Verified 280.5k+ views Hint: First we have to define what the terms we need to solve the problem are. Since a number is need to be multiplied by X and exceeds itself as 64 and we need to find that unknown number using some formula; (multiplied term) into X equals to X sum of 64, and the options are to between the numbers are fourteen, sixteen, eight and eighteen. Complete step by step answer: As we see the given question as a number is multiplied by number five and exceeds the number sixty-four; which means five times of unknown X equals the sum of X and sixty-four. Which is \Rightarrow 5X = X + 64(from the given know things we can able to say this) Hence further solving the above equation as per the cancelling law or turn the right-hand side X into the left-hand side; as follows \Rightarrow 5X = X + 64 \Rightarrow 5X - X = 64(X will passed into right to left side) \Rightarrow 5X - X = 64 \Rightarrow 4X = 64(Five subtracts one yield four) \Rightarrow 4X = 64 \Rightarrow X = 16(Cancelling both sides with respect to four will be left side one will occur and in right side sixteen will occur) Hence option B)$$16$is the correct option;
Thus, all other options are eliminated and hence option $B)$$16$ is correct.
Note: Since the unknown term is the multiplied by five times and exceed by sixteen which is sum of sixty-four thus only we make X as the unknown term and formed a formula like $\Rightarrow 5X = X + 64$