What is the final product of glycolysis – pyruvic acid/glucose/malic acid/phosphoglyceric acid/acetyl CoA/phosphoric acid.
Answer
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Hint: It took 100 years to discover this process. It forms the basic process in our metabolism. The energy required in our body is generated via a long cascade. It was introduced by Harden and William Young.
Complete answer:
Glycolysis is the process of conversion of glucose to the simpler forms that is two molecules of pyruvate or pyruvic acid. It is an anaerobic pathway which is of ten steps. It utilizes energy in the first half and produces ATP in the second half. It is an enzyme catalysed process. Any form of monosaccharide can be converted and reduced.
It has two phases- the preparatory phase and the payoff phase.
The preparatory phase is an investment phase which consumes energy to convert glucose into three-carbon compounds. There are various enzymes like hexokinase, isomerases etc.
The pay off phase is the net gain of ATP and NADH. This occurs twice to treat the two three-molecule sugar compounds. It gives us 4 ATP and 2 NADH at the end producing the pyruvic acid.
Pyruvic acid ($C{H_3}CO.COOH$) is the alpha-keto acid with carboxylic acid and a ketone group. It can be converted to ethanol or lactic acid via the fermentation process. In the presence of oxygen, the pyruvic acid is produced. While in the absence of oxygen, ethanol is produced.
Pyruvic acid under the TCA cycle to give acetyl CoA.
So the answer is Pyruvic acid/pyruvate.
Note: It is the fastest process of producing ATP or energy. It initiates in the cytoplasm of the cell but is completed in the mitochondria. It occurs in both the prokaryotes and eukaryotes. It can occur both aerobically and anaerobically.
Complete answer:
Glycolysis is the process of conversion of glucose to the simpler forms that is two molecules of pyruvate or pyruvic acid. It is an anaerobic pathway which is of ten steps. It utilizes energy in the first half and produces ATP in the second half. It is an enzyme catalysed process. Any form of monosaccharide can be converted and reduced.
It has two phases- the preparatory phase and the payoff phase.
The preparatory phase is an investment phase which consumes energy to convert glucose into three-carbon compounds. There are various enzymes like hexokinase, isomerases etc.
The pay off phase is the net gain of ATP and NADH. This occurs twice to treat the two three-molecule sugar compounds. It gives us 4 ATP and 2 NADH at the end producing the pyruvic acid.
Pyruvic acid ($C{H_3}CO.COOH$) is the alpha-keto acid with carboxylic acid and a ketone group. It can be converted to ethanol or lactic acid via the fermentation process. In the presence of oxygen, the pyruvic acid is produced. While in the absence of oxygen, ethanol is produced.
Pyruvic acid under the TCA cycle to give acetyl CoA.
So the answer is Pyruvic acid/pyruvate.
Note: It is the fastest process of producing ATP or energy. It initiates in the cytoplasm of the cell but is completed in the mitochondria. It occurs in both the prokaryotes and eukaryotes. It can occur both aerobically and anaerobically.
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