
Factorize ${x^2} + 4x + 3$
Answer
497.7k+ views
Hint: Factorization: factorization or factoring consists of writing a number or another mathematical object as a product of several factors, usually smaller or simpler objects of the same kind.
To solve this question we should first try to split the middle term which is given with respect to the product of coefficients of first and last term. Then we will take a common and try to reduce it further.
Complete answer:As given,
${x^2} + 4x + 3$
We have to factorize it.
Show we will take coefficient and first and last constant term.
Here, $a = 1\,and\,c = 3$
And $b = 4$
Product of $a\,and\,b = 3 \times 1 = 3$
So, we will split 4 will in respect to 3.
So, we can write $4 = 3 + 1$
Let keeping it in equation:
${x^2} + 4x + 3$
Keep as above calculated:
${x^2} + (3 + 1)x + 3$
Open the bracket,
${x^2} + x + 3x + 3$
Take common from first two and last two terms.
$x(x + 1) + 3(x + 1)$
Take the common from it. We get,
$ = (x + 1)\left( {x + 3} \right)$
So, on doing the Factorization,we have ${x^2} + 4x + 3 = (x + 1)\left( {x + 3} \right)$
Note:
If you want to calculate zeros of a given quadratic equation. Then we will keep it equal to zero.
As,
$(x + 1)\left( {x + 3} \right) = 0$
So, $(x + 1) = 0$
$ \Rightarrow x = - 1$
And $\left( {x + 3} \right) = 0$
$ \Rightarrow x = - 3$
Zero: It is the value at which our given equation will be zero.
To solve this question we should first try to split the middle term which is given with respect to the product of coefficients of first and last term. Then we will take a common and try to reduce it further.
Complete answer:As given,
${x^2} + 4x + 3$
We have to factorize it.
Show we will take coefficient and first and last constant term.
Here, $a = 1\,and\,c = 3$
And $b = 4$
Product of $a\,and\,b = 3 \times 1 = 3$
So, we will split 4 will in respect to 3.
So, we can write $4 = 3 + 1$
Let keeping it in equation:
${x^2} + 4x + 3$
Keep as above calculated:
${x^2} + (3 + 1)x + 3$
Open the bracket,
${x^2} + x + 3x + 3$
Take common from first two and last two terms.
$x(x + 1) + 3(x + 1)$
Take the common from it. We get,
$ = (x + 1)\left( {x + 3} \right)$
So, on doing the Factorization,we have ${x^2} + 4x + 3 = (x + 1)\left( {x + 3} \right)$
Note:
If you want to calculate zeros of a given quadratic equation. Then we will keep it equal to zero.
As,
$(x + 1)\left( {x + 3} \right) = 0$
So, $(x + 1) = 0$
$ \Rightarrow x = - 1$
And $\left( {x + 3} \right) = 0$
$ \Rightarrow x = - 3$
Zero: It is the value at which our given equation will be zero.
Recently Updated Pages
Master Class 10 Computer Science: Engaging Questions & Answers for Success

Master Class 10 General Knowledge: Engaging Questions & Answers for Success

Master Class 10 English: Engaging Questions & Answers for Success

Master Class 10 Social Science: Engaging Questions & Answers for Success

Master Class 10 Maths: Engaging Questions & Answers for Success

Master Class 10 Science: Engaging Questions & Answers for Success

Trending doubts
What is the median of the first 10 natural numbers class 10 maths CBSE

Which women's tennis player has 24 Grand Slam singles titles?

Who is the Brand Ambassador of Incredible India?

Why is there a time difference of about 5 hours between class 10 social science CBSE

Write a letter to the principal requesting him to grant class 10 english CBSE

A moving boat is observed from the top of a 150 m high class 10 maths CBSE

