
How do you factor $4{{x}^{2}}+2x-20$?
(a) Factor by grouping
(b) Zero putting
(c) Guessing the factors
(d) None of the above
Answer
449.7k+ views
Hint: To find the factor of the given equation $4{{x}^{2}}+2x-20$, we will try to factorize it by grouping them among terms. First we will check if we can take any factor common from all of the terms like 2. Again, we will start off with multiplying the coefficients of the first and last terms as 2 and 10 and then factorize them to get the middle term of the equation 1. Then by taking the proper terms common we can get the needed answer and factorization.
Complete step-by-step answer:
According to the question, our given equation as, $4{{x}^{2}}+2x-20$and we are to factorize this equation.
So, to start with, we have,
$4{{x}^{2}}+2x-20$
As, we are trying to factorize this with grouping, we will start by taking 2 common from all of the terms,
$=2(2{{x}^{2}}+x-10)$
One has to determine all the terms that were multiplied to obtain the given polynomial. Then try to factor every term that you got in the first step and this continues until you cannot factor further. When you can’t perform any more factoring, it is said that the polynomial is factored completely.
Again, we can factorize $2{{x}^{2}}+x-10$ by factorization with the process of middle term,
So, now we have,
$2{{x}^{2}}+x-10$
Now, x can be written as 5x - 4x, so,
$\Rightarrow 2{{x}^{2}}+5x-4x-10$
So, we can take x common from first two terms and -2 common from the last two terms,
$\Rightarrow x(2x+5)-2(2x+5)$
Getting the terms together, we get,
$\Rightarrow (2x+5)(x-2)$
So, by factoring $4{{x}^{2}}+2x-20$we get, $2(2x+5)(x-2)$ .
Hence the solution is, (a) Factor by grouping.
Note: A polynomial $4{{x}^{2}}+2x-20$ can be written as a product of two or more polynomials of degree less than or equal to that of it. Each polynomial involved in the product will be a factor of it. Monomials can be factorized in the same way as integers, just by writing the monomial as the product of its constituent prime factors. In the case of monomials, these prime factors can be integers as well as other monomials which cannot be factored further.
Complete step-by-step answer:
According to the question, our given equation as, $4{{x}^{2}}+2x-20$and we are to factorize this equation.
So, to start with, we have,
$4{{x}^{2}}+2x-20$
As, we are trying to factorize this with grouping, we will start by taking 2 common from all of the terms,
$=2(2{{x}^{2}}+x-10)$
One has to determine all the terms that were multiplied to obtain the given polynomial. Then try to factor every term that you got in the first step and this continues until you cannot factor further. When you can’t perform any more factoring, it is said that the polynomial is factored completely.
Again, we can factorize $2{{x}^{2}}+x-10$ by factorization with the process of middle term,
So, now we have,
$2{{x}^{2}}+x-10$
Now, x can be written as 5x - 4x, so,
$\Rightarrow 2{{x}^{2}}+5x-4x-10$
So, we can take x common from first two terms and -2 common from the last two terms,
$\Rightarrow x(2x+5)-2(2x+5)$
Getting the terms together, we get,
$\Rightarrow (2x+5)(x-2)$
So, by factoring $4{{x}^{2}}+2x-20$we get, $2(2x+5)(x-2)$ .
Hence the solution is, (a) Factor by grouping.
Note: A polynomial $4{{x}^{2}}+2x-20$ can be written as a product of two or more polynomials of degree less than or equal to that of it. Each polynomial involved in the product will be a factor of it. Monomials can be factorized in the same way as integers, just by writing the monomial as the product of its constituent prime factors. In the case of monomials, these prime factors can be integers as well as other monomials which cannot be factored further.
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