Answer
358.4k+ views
Hint: Keep a decimal point into one digit and convert others into terms of $10$.
Now in question it is asked to convert the number in standard form,
It is difficult to read numbers like$1202000004240$ or $0.0000042852512$. To make it easy
to read very large and small numbers, we write them in standard form.
So first of all what is standard form,
Standard form is a way of writing down very large or very small numbers
easily.${{10}^{3}}=1000$, so $4\times {{10}^{3}}=4000$ . So $4000$ can be written as$4\times {{10}^{3}}$ . This idea can be used to write even larger numbers down easily in
standard form. Any number that we can write as a decimal number, between $1.0$ and
$10.0$, multiplied by a power of $10$, is said to be in standard form.
Standard form in Math is mentioned for basically decimal numbers, equations, polynomials,
linear equations, etc. Its correct definition could be explained better in terms of decimal
numbers and following certain rules.
As we know, the decimal numbers are the simplified form of fractions. Some fractions give
decimal numbers which have numbers after decimal in thousandths, hundredths or tenths
place. But there are some fractions, which gives a big decimal number.
To represent such big numbers, we use such simpler forms, which is also stated as Scientific
notation.
Let us take an example $43333.21$
So we can write $43333.21=4.333321\times {{10}^{4}}$……..(1)
In the (1) we can see it, So $4.333321\times {{10}^{4}}$is standard form of $43333.21$.
So in this way we can write the digits in standard form.
So generally Standard form is a way of writing down very large or very small numbers easily.
Now for us given number is $3908.78$ ,
So we have to convert $3908.78$ in standard form,
Multiplying and dividing by 100 to $3908.78$, We get
$=\dfrac{3908.78\times 100}{100}=\dfrac{390878}{100}$
Now simplifying it We get
$=\dfrac{3.90878\times {{10}^{5}}}{100}=\dfrac{3.90878\times {{10}^{5}}}{{{10}^{2}}}$…… (2)
Now we know the property that $\dfrac{{{a}^{m}}}{{{a}^{n}}}={{a}^{m-n}}$,
So using the above property in (2) We get,
$\begin{align}
& =\dfrac{3.90878\times {{10}^{5}}}{{{10}^{2}}}=3.90878\times \dfrac{{{10}^{5}}}{{{10}^{2}}}=3.90878\times {{10}^{5-2}} \\
& =3.90878\times {{10}^{3}} \\
\end{align}$
So $3.90878\times {{10}^{3}}$ is standard form of $3908.78$.
So we have got the standard form of $3908.78$ which is $3.90878\times {{10}^{3}}$.
Hence proved.
$3.90878\times {{10}^{3}}$ is standard form of $3908.78$ is the answer.
Note: So basically don’t jumble while converting the number. Such as $3908.78$ to $3.90878\times {{10}^{3}}$. Use the property accordingly Such as I had used this property
$\dfrac{{{a}^{m}}}{{{a}^{n}}}={{a}^{m-n}}$. Remember that the properties are used according
to the problem.
Now in question it is asked to convert the number in standard form,
It is difficult to read numbers like$1202000004240$ or $0.0000042852512$. To make it easy
to read very large and small numbers, we write them in standard form.
So first of all what is standard form,
Standard form is a way of writing down very large or very small numbers
easily.${{10}^{3}}=1000$, so $4\times {{10}^{3}}=4000$ . So $4000$ can be written as$4\times {{10}^{3}}$ . This idea can be used to write even larger numbers down easily in
standard form. Any number that we can write as a decimal number, between $1.0$ and
$10.0$, multiplied by a power of $10$, is said to be in standard form.
Standard form in Math is mentioned for basically decimal numbers, equations, polynomials,
linear equations, etc. Its correct definition could be explained better in terms of decimal
numbers and following certain rules.
As we know, the decimal numbers are the simplified form of fractions. Some fractions give
decimal numbers which have numbers after decimal in thousandths, hundredths or tenths
place. But there are some fractions, which gives a big decimal number.
To represent such big numbers, we use such simpler forms, which is also stated as Scientific
notation.
Let us take an example $43333.21$
So we can write $43333.21=4.333321\times {{10}^{4}}$……..(1)
In the (1) we can see it, So $4.333321\times {{10}^{4}}$is standard form of $43333.21$.
So in this way we can write the digits in standard form.
So generally Standard form is a way of writing down very large or very small numbers easily.
Now for us given number is $3908.78$ ,
So we have to convert $3908.78$ in standard form,
Multiplying and dividing by 100 to $3908.78$, We get
$=\dfrac{3908.78\times 100}{100}=\dfrac{390878}{100}$
Now simplifying it We get
$=\dfrac{3.90878\times {{10}^{5}}}{100}=\dfrac{3.90878\times {{10}^{5}}}{{{10}^{2}}}$…… (2)
Now we know the property that $\dfrac{{{a}^{m}}}{{{a}^{n}}}={{a}^{m-n}}$,
So using the above property in (2) We get,
$\begin{align}
& =\dfrac{3.90878\times {{10}^{5}}}{{{10}^{2}}}=3.90878\times \dfrac{{{10}^{5}}}{{{10}^{2}}}=3.90878\times {{10}^{5-2}} \\
& =3.90878\times {{10}^{3}} \\
\end{align}$
So $3.90878\times {{10}^{3}}$ is standard form of $3908.78$.
So we have got the standard form of $3908.78$ which is $3.90878\times {{10}^{3}}$.
Hence proved.
$3.90878\times {{10}^{3}}$ is standard form of $3908.78$ is the answer.
Note: So basically don’t jumble while converting the number. Such as $3908.78$ to $3.90878\times {{10}^{3}}$. Use the property accordingly Such as I had used this property
$\dfrac{{{a}^{m}}}{{{a}^{n}}}={{a}^{m-n}}$. Remember that the properties are used according
to the problem.
Recently Updated Pages
How many sigma and pi bonds are present in HCequiv class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Why Are Noble Gases NonReactive class 11 chemistry CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let X and Y be the sets of all positive divisors of class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x and y be 2 real numbers which satisfy the equations class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x 4log 2sqrt 9k 1 + 7 and y dfrac132log 2sqrt5 class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Let x22ax+b20 and x22bx+a20 be two equations Then the class 11 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Trending doubts
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
At which age domestication of animals started A Neolithic class 11 social science CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Which are the Top 10 Largest Countries of the World?
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Give 10 examples for herbs , shrubs , climbers , creepers
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Difference Between Plant Cell and Animal Cell
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Write a letter to the principal requesting him to grant class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Change the following sentences into negative and interrogative class 10 english CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)
Fill in the blanks A 1 lakh ten thousand B 1 million class 9 maths CBSE
![arrow-right](/cdn/images/seo-templates/arrow-right.png)