
Express the distance $150 \times {10^6}\,km$ in light years.
Answer
477.6k+ views
Hint: In order to solve this question, we will first know the definition of a light year. One light year is the distance travelled by light in one year. One light year is equal to $9.46 \times {10^{12}}\,km$. Now, we will be using the unitary method to express the given distance in light years. Suppose, we buy $5$ pencils for rupees $25$ and we want to know the price of $15$ pencils. So, in such a type of problem, we use a unitary method. So, we have, cost of five pencils $ = Rs\,25$
Cost of one pencil $ = Rs\,\dfrac{{25}}{5} = Rs\,5$
Now, cost of $15$pencils $ = 15 \times Rs\,5 = Rs\,75$
Complete step by step answer:
Now, we know that one light year is a unit of astronomical distance that light travels in one year. One light year is equal to $ = 9.46 \times {10^{12}}km$. So, we have,
$9.46 \times {10^{12}}\,km = 1$ light year
Now, finding the value of one kilometre in terms of a light year, we get,
$ \Rightarrow 1\,km = \dfrac{1}{{9.46 \times {{10}^{12}}}}$ light years
Now, we have to find the value of $150 \times {10^6}\,km$ in terms of light year. So, we multiply both sides of the equation by $150 \times {10^6}$.
Hence, we get,
$ \Rightarrow 150 \times {10^6}\,km = \dfrac{1}{{9.46 \times {{10}^{12}}}} \times 150 \times {10^6}$ light year
Simplifying the expression, we get,
$ \Rightarrow 150 \times {10^6}\,km = \dfrac{{15}}{{9.46 \times {{10}^5}}}$ light year
Doing the calculations, we get,
$\therefore 150 \times {10^6}\,km = 1.586 \times {10^{ - 5}}$ light year
So, $150 \times {10^6}\,km$is equivalent to $1.586 \times {10^{ - 5}}$ light years.
Note: Objects in our universe are extremely far away. Light year is used to measure astronomical distances. It is denoted by ly, and the value is $9.46 \times {10^{12}}km$. Mostly light years are used to measure distance from the star. Light moves at a velocity of about $3 \times {10^8}m/s$ which is the fastest moving stuff in our universe so, in one light year, it can travel about 10 trillion km.
Cost of one pencil $ = Rs\,\dfrac{{25}}{5} = Rs\,5$
Now, cost of $15$pencils $ = 15 \times Rs\,5 = Rs\,75$
Complete step by step answer:
Now, we know that one light year is a unit of astronomical distance that light travels in one year. One light year is equal to $ = 9.46 \times {10^{12}}km$. So, we have,
$9.46 \times {10^{12}}\,km = 1$ light year
Now, finding the value of one kilometre in terms of a light year, we get,
$ \Rightarrow 1\,km = \dfrac{1}{{9.46 \times {{10}^{12}}}}$ light years
Now, we have to find the value of $150 \times {10^6}\,km$ in terms of light year. So, we multiply both sides of the equation by $150 \times {10^6}$.
Hence, we get,
$ \Rightarrow 150 \times {10^6}\,km = \dfrac{1}{{9.46 \times {{10}^{12}}}} \times 150 \times {10^6}$ light year
Simplifying the expression, we get,
$ \Rightarrow 150 \times {10^6}\,km = \dfrac{{15}}{{9.46 \times {{10}^5}}}$ light year
Doing the calculations, we get,
$\therefore 150 \times {10^6}\,km = 1.586 \times {10^{ - 5}}$ light year
So, $150 \times {10^6}\,km$is equivalent to $1.586 \times {10^{ - 5}}$ light years.
Note: Objects in our universe are extremely far away. Light year is used to measure astronomical distances. It is denoted by ly, and the value is $9.46 \times {10^{12}}km$. Mostly light years are used to measure distance from the star. Light moves at a velocity of about $3 \times {10^8}m/s$ which is the fastest moving stuff in our universe so, in one light year, it can travel about 10 trillion km.
Recently Updated Pages
Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Biology: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 8 Maths: Engaging Questions & Answers for Success

Class 8 Question and Answer - Your Ultimate Solutions Guide

Trending doubts
Which animal has three hearts class 11 biology CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Explain zero factorial class 11 maths CBSE

Mention the basic forces in nature class 11 physics CBSE

What is centripetal acceleration Derive the expression class 11 physics CBSE

Bond order ofO2 O2+ O2 and O22 is in order A O2 langle class 11 chemistry CBSE

