
Express mass of $6.022 \times {10^{22}}$ molecules of $C{O_2}$ in grams.
Answer
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Hint: Carbon dioxide is a type of hetero atomic molecule because it consist of more than one type of atoms. Since carbon dioxide has a total of three atoms it is also known as a triatomic molecule.
The number $6.022 \times {10^{23}}$ is known as the Avogadro number.
Complete answer:
One mole of any compound contains a total number of molecules equal to Avogadro number.
Hence, $1$ mole of $C{O_2}$ contains a total number of $6.022 \times {10^{23}}$ particles or molecules.
Molecular weight of $1$ mole of $C{O_2}$ is equal to the sum of atomic mass of carbon and oxygen.
Atomic weight of $\left( C \right)$ is $12g$
Atomic weight of $\left( O \right)$ is $16g$
$M = 12 + 2 \times 16g$
After solving we get, Molecular weight of $1$ mole of $C{O_2}$ is $ = 44g$
As we know that each mole of carbon dioxide contains $6.022 \times {10^{23}}$ molecules so, $44g$ of carbon dioxide also contains the same amount of molecules.
Mass of $6.022 \times {10^{23}}$ particles of $C{O_2}$ in grams is equal to its molecular mass in grams i.e.$\left( {44g} \right)$
$1$ mole of $C{O_2}$$ = 6.022 \times {10^{23}}$ molecules of $C{O_2}$$ = 44g$ of $C{O_2}$
Hence, $1$ molecule of $C{O_2}$ weigh $ = \dfrac{{44}}{{6.022 \times {{10}^{23}}}}g$ of $C{O_2}$
So $6.022 \times {10^{22}}$ molecule of $C{O_2}$ weigh $ = \dfrac{{44}}{{6.022 \times {{10}^{23}}}} \times 6.022 \times {10^{22}}g$ of $C{O_2}$
After solving the above equation we get,
$6.022 \times {10^{22}}$molecule of $C{O_2}$ weigh $ = 44 \times 0.1g$ of $C{O_2}$
$6.022 \times {10^{22}}$ molecule of $C{O_2}$ weigh $ = 4.4g$ of $C{O_2}$
Hence, weight of $6.022 \times {10^{22}}$ molecule of $C{O_2}$ is $4.4g$
Note:
Avogadro number remains the same for one mole of any atom. It is alphabetically represented as ${N_A}$.
Do not forget to consider the atomic mass of every constituting atom in units of grams.
$C{O_{2\left( g \right)}}$ Is a major responsible gas for causing global warming and it also gets converted into carbonic acid which is a component of acid rain.
The number $6.022 \times {10^{23}}$ is known as the Avogadro number.
Complete answer:
One mole of any compound contains a total number of molecules equal to Avogadro number.
Hence, $1$ mole of $C{O_2}$ contains a total number of $6.022 \times {10^{23}}$ particles or molecules.
Molecular weight of $1$ mole of $C{O_2}$ is equal to the sum of atomic mass of carbon and oxygen.
Atomic weight of $\left( C \right)$ is $12g$
Atomic weight of $\left( O \right)$ is $16g$
$M = 12 + 2 \times 16g$
After solving we get, Molecular weight of $1$ mole of $C{O_2}$ is $ = 44g$
As we know that each mole of carbon dioxide contains $6.022 \times {10^{23}}$ molecules so, $44g$ of carbon dioxide also contains the same amount of molecules.
Mass of $6.022 \times {10^{23}}$ particles of $C{O_2}$ in grams is equal to its molecular mass in grams i.e.$\left( {44g} \right)$
$1$ mole of $C{O_2}$$ = 6.022 \times {10^{23}}$ molecules of $C{O_2}$$ = 44g$ of $C{O_2}$
Hence, $1$ molecule of $C{O_2}$ weigh $ = \dfrac{{44}}{{6.022 \times {{10}^{23}}}}g$ of $C{O_2}$
So $6.022 \times {10^{22}}$ molecule of $C{O_2}$ weigh $ = \dfrac{{44}}{{6.022 \times {{10}^{23}}}} \times 6.022 \times {10^{22}}g$ of $C{O_2}$
After solving the above equation we get,
$6.022 \times {10^{22}}$molecule of $C{O_2}$ weigh $ = 44 \times 0.1g$ of $C{O_2}$
$6.022 \times {10^{22}}$ molecule of $C{O_2}$ weigh $ = 4.4g$ of $C{O_2}$
Hence, weight of $6.022 \times {10^{22}}$ molecule of $C{O_2}$ is $4.4g$
Note:
Avogadro number remains the same for one mole of any atom. It is alphabetically represented as ${N_A}$.
Do not forget to consider the atomic mass of every constituting atom in units of grams.
$C{O_{2\left( g \right)}}$ Is a major responsible gas for causing global warming and it also gets converted into carbonic acid which is a component of acid rain.
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