Express in terms of a right angle, the angle \[{{75}^{\circ }}15'\].
Answer
624.9k+ views
Hint: We know that a right angle is equal to \[{{90}^{\circ }}\]. We will first convert the given angle in degrees completely for which we will use the following conversion:
\[1'={{\left( \dfrac{1}{60} \right)}^{\circ }}\]
After converting the given angle completely into degree we will suppose the given angle is equal to ‘k’ times the right angle and thus equating them we will find the value of ‘k’.
Complete step-by-step answer:
We have been given the angle \[{{75}^{\circ }}15'\] which we have to express in terms of right angle.
We know that \[1'={{\left( \dfrac{1}{60} \right)}^{\circ }}\]
\[\Rightarrow 15'={{\left( 15\times \dfrac{1}{60} \right)}^{\circ }}={{0.25}^{\circ }}\]
So \[{{75}^{\circ }}15'\] is equal to \[\left( {{75}^{\circ }}+15' \right)\].
\[\Rightarrow {{75}^{\circ }}15'=\left( {{75}^{\circ }}+15' \right)\]
Substituting the value of 15’ in the terms of degree, we get as follows:
\[\Rightarrow {{75}^{\circ }}15'=\left( {{75}^{\circ }}+{{0.25}^{\circ }} \right)={{75.25}^{\circ }}\]
Let us suppose \[{{75.25}^{\circ }}\] is equal to k times a right angle \[\left( {{90}^{\circ }} \right)\].
\[\Rightarrow {{75.25}^{\circ }}=k\times {{90}^{\circ }}\]
On dividing the equation by \[{{90}^{\circ }}\], we get as follows:
\[\begin{align}
& \Rightarrow \dfrac{{{75.25}^{\circ }}}{{{90}^{\circ }}}=\dfrac{k\times {{90}^{\circ }}}{{{90}^{\circ }}} \\
& \Rightarrow \dfrac{301}{360}=k \\
\end{align}\]
Therefore, the angle \[{{75}^{\circ }}15'\] can be expressed in terms of a right angle as \[\dfrac{301}{360}\] times of a right angle.
Note: In this type of questions, first of all check that the given angle is completely either in degree or radians. Then suppose the angle to be equal to k times the right angle and the unit of measurement must be the same. If the given angle is in degrees then you will take right angle equal to \[{{90}^{\circ }}\] and if the given angle is in radians then you will take right angle is equal to \[\dfrac{\pi }{2}\] radians. Also, sometimes in order to calculate the values of ‘k’, we just divide \[{{90}^{\circ }}\] the given angle by mistake. So be careful while calculating the value of k.
\[1'={{\left( \dfrac{1}{60} \right)}^{\circ }}\]
After converting the given angle completely into degree we will suppose the given angle is equal to ‘k’ times the right angle and thus equating them we will find the value of ‘k’.
Complete step-by-step answer:
We have been given the angle \[{{75}^{\circ }}15'\] which we have to express in terms of right angle.
We know that \[1'={{\left( \dfrac{1}{60} \right)}^{\circ }}\]
\[\Rightarrow 15'={{\left( 15\times \dfrac{1}{60} \right)}^{\circ }}={{0.25}^{\circ }}\]
So \[{{75}^{\circ }}15'\] is equal to \[\left( {{75}^{\circ }}+15' \right)\].
\[\Rightarrow {{75}^{\circ }}15'=\left( {{75}^{\circ }}+15' \right)\]
Substituting the value of 15’ in the terms of degree, we get as follows:
\[\Rightarrow {{75}^{\circ }}15'=\left( {{75}^{\circ }}+{{0.25}^{\circ }} \right)={{75.25}^{\circ }}\]
Let us suppose \[{{75.25}^{\circ }}\] is equal to k times a right angle \[\left( {{90}^{\circ }} \right)\].
\[\Rightarrow {{75.25}^{\circ }}=k\times {{90}^{\circ }}\]
On dividing the equation by \[{{90}^{\circ }}\], we get as follows:
\[\begin{align}
& \Rightarrow \dfrac{{{75.25}^{\circ }}}{{{90}^{\circ }}}=\dfrac{k\times {{90}^{\circ }}}{{{90}^{\circ }}} \\
& \Rightarrow \dfrac{301}{360}=k \\
\end{align}\]
Therefore, the angle \[{{75}^{\circ }}15'\] can be expressed in terms of a right angle as \[\dfrac{301}{360}\] times of a right angle.
Note: In this type of questions, first of all check that the given angle is completely either in degree or radians. Then suppose the angle to be equal to k times the right angle and the unit of measurement must be the same. If the given angle is in degrees then you will take right angle equal to \[{{90}^{\circ }}\] and if the given angle is in radians then you will take right angle is equal to \[\dfrac{\pi }{2}\] radians. Also, sometimes in order to calculate the values of ‘k’, we just divide \[{{90}^{\circ }}\] the given angle by mistake. So be careful while calculating the value of k.
Recently Updated Pages
Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Chemistry: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

State and prove Bernoullis theorem class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

Which among the following are examples of coming together class 11 social science CBSE

