Explain the process of finding the dimensional formula of universal gravitational constant (G) and mention its SI unit.
Answer
605.4k+ views
Hint: Apply the Newton’s law of universal gravitation i.e., all objects attract each other with a force of gravitational attraction. This force of gravitational attraction is directly proportional to the product of masses of both objects and inversely proportional to the square of the distance between them. Mathematically it is given by, \[F=\dfrac{G{{m}_{1}}{{m}_{2}}}{{{r}^{2}}}\]
Complete answer:
According to Newton's law of universal gravitation, the force of gravitational attraction is given by,
\[F=\dfrac{G{{m}_{1}}{{m}_{2}}}{{{r}^{2}}}\]
Where,
F = gravitational force of attraction
G = universal gravitational constant
m1 = mass of an object
m2 = mass of another object
r = distance between two objects
Which can be written as,
\[G=\dfrac{F{{r}^{2}}}{{{m}_{1}}{{m}_{2}}}\]
Now for finding the dimension formula of universal gravitational constant G,
we need to write dimensional formula of each quantity in right hand side i.e.,
The dimensional formula of G = \[\dfrac{\left[ \text{ML}{{\text{T}}^{\text{-2}}} \right]\left[ {{\text{L}}^{\text{2}}} \right]}{\left[ \text{M} \right]\left[ \text{M} \right]}\]
\[\Rightarrow \dfrac{\left[ \text{ML}{{\text{T}}^{\text{-2}}} \right]\left[ {{\text{L}}^{\text{2}}} \right]}{\left[ {{\text{M}}^{2}} \right]}\]
\[\Rightarrow \left[ {{\text{M}}^{\text{-1}}}\text{L}{{\text{T}}^{\text{-2}}} \right]\left[ {{\text{L}}^{\text{2}}} \right]\]
\[\Rightarrow \left[ {{\text{M}}^{\text{-1}}}{{\text{L}}^{3}}{{\text{T}}^{\text{-2}}} \right]\]
So, the dimensional formula of universal gravitational constant G is, \[\left[ {{\text{M}}^{\text{-1}}}{{\text{L}}^{3}}{{\text{T}}^{\text{-2}}} \right]\]
And the SI unit of universal gravitational constant (G) is $N{kg^{-2}}{m^2}$
Additional Information:
The gravitational force is directly proportional to the mass of both interacting objects, more massive objects will attract each other with a relatively greater gravitational force. So as the mass of either object increases, the force of gravitational attraction between them also increases. If the mass of one of the objects is doubled, then the force of gravity between them is also doubled.
The gravitational force is inversely proportional to the square of the distance between the two interacting objects, more distance will result in relatively weaker gravitational forces. So as two objects are separated from each other, the force of gravitational attraction between them also decreases.
Note:
Students should understand Newton's law of universal gravitation so that they can write the formula for force of attraction easily. Thereafter students need to write the dimensional formula of each and every quantity in the right hand side, in this way they will get the required dimensional formula. There is one more method to find out the dimensional formula of universal gravitational constant G, by the relation between g and G i.e., \[g=\dfrac{Gm}{{{r}^{2}}}\]. In this method students need to make G as a subject and write dimensional formulas for the quantities in the right hand side.
Complete answer:
According to Newton's law of universal gravitation, the force of gravitational attraction is given by,
\[F=\dfrac{G{{m}_{1}}{{m}_{2}}}{{{r}^{2}}}\]
Where,
F = gravitational force of attraction
G = universal gravitational constant
m1 = mass of an object
m2 = mass of another object
r = distance between two objects
Which can be written as,
\[G=\dfrac{F{{r}^{2}}}{{{m}_{1}}{{m}_{2}}}\]
Now for finding the dimension formula of universal gravitational constant G,
we need to write dimensional formula of each quantity in right hand side i.e.,
The dimensional formula of G = \[\dfrac{\left[ \text{ML}{{\text{T}}^{\text{-2}}} \right]\left[ {{\text{L}}^{\text{2}}} \right]}{\left[ \text{M} \right]\left[ \text{M} \right]}\]
\[\Rightarrow \dfrac{\left[ \text{ML}{{\text{T}}^{\text{-2}}} \right]\left[ {{\text{L}}^{\text{2}}} \right]}{\left[ {{\text{M}}^{2}} \right]}\]
\[\Rightarrow \left[ {{\text{M}}^{\text{-1}}}\text{L}{{\text{T}}^{\text{-2}}} \right]\left[ {{\text{L}}^{\text{2}}} \right]\]
\[\Rightarrow \left[ {{\text{M}}^{\text{-1}}}{{\text{L}}^{3}}{{\text{T}}^{\text{-2}}} \right]\]
So, the dimensional formula of universal gravitational constant G is, \[\left[ {{\text{M}}^{\text{-1}}}{{\text{L}}^{3}}{{\text{T}}^{\text{-2}}} \right]\]
And the SI unit of universal gravitational constant (G) is $N{kg^{-2}}{m^2}$
Additional Information:
The gravitational force is directly proportional to the mass of both interacting objects, more massive objects will attract each other with a relatively greater gravitational force. So as the mass of either object increases, the force of gravitational attraction between them also increases. If the mass of one of the objects is doubled, then the force of gravity between them is also doubled.
The gravitational force is inversely proportional to the square of the distance between the two interacting objects, more distance will result in relatively weaker gravitational forces. So as two objects are separated from each other, the force of gravitational attraction between them also decreases.
Note:
Students should understand Newton's law of universal gravitation so that they can write the formula for force of attraction easily. Thereafter students need to write the dimensional formula of each and every quantity in the right hand side, in this way they will get the required dimensional formula. There is one more method to find out the dimensional formula of universal gravitational constant G, by the relation between g and G i.e., \[g=\dfrac{Gm}{{{r}^{2}}}\]. In this method students need to make G as a subject and write dimensional formulas for the quantities in the right hand side.
Recently Updated Pages
If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

A car covers the first half distance between two places class 11 physics CBSE

The resultant of two vectors overrightarrow P and overrightarrow class 11 physics CBSE

Find the value of cos 135 class 11 maths CBSE

A mass M is held in place by an applied force F and class 11 physics CBSE

A solution of glucose in water is labelled as 10 dfracwv class 11 chemistry CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Find the value of the expression given below sin 30circ class 11 maths CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

Bond order ofO2 O2+ O2 and O22 is in order A O2 langle class 11 chemistry CBSE

