Question

Explain how you can find the simplest form of $\dfrac{100}{1000}$?

Answer 1

Hint: In the question we are asked to find the simplest form of $\dfrac{100}{1000}$. In order to do this question, you just have to cancel out the same number of zeroes on both numerator and denominator. If you suppose you have four zeros in the numerator and 5 zeroes in the denominator, you have to cancel all the four zeroes in the numerator and only four zeroes in the denominator. Then you can see if the term is divisible by a number on both the numerator and denominator.

Complete step by step solution:
In the given question we have to find the simplest form of $\dfrac{100}{1000}$.
To solve this, we have to cancel out the same number of zeroes on both numerator and denominator. Then we have to see if the term is divisible by a number on both the numerator and denominator.
First we take $\dfrac{100}{1000}$ as x:
$ x=\dfrac{100}{1000}$
Then we have to cancel the zeroes.
$x=\dfrac{1}{10}$
We can see that $\dfrac{1}{10}$ cannot be further divided by any number. Therefore $\dfrac{1}{10}$ is the simplest form of $\dfrac{100}{1000}$

Therefore, we get the final of the question - explain how you can find the simplest form of $\dfrac{100}{1000}$ as $\dfrac{1}{10}$.

Note: This question is fairly simple. Here you just have to cancel out the zeroes. But you may get hard questions like $\dfrac{234}{534}$. Here you have to see the common divisor between the two and convert it to the simple form. For the given example, we can clearly see that 2 is a common divisor. So, we have to divide the numerator and the denominator with 2 and then we have to see if it is further reducible.