
How do you expand $ {(r + 3)^5} $ using Pascal’s Triangle?
Answer
542.1k+ views
Hint: We will start off by explaining Pascal's Triangle. Then mention its different forms and rules. Then we will mention the expansion. After that we will compare the coefficients and then substitute in the formula and then simplify the terms.
Complete step-by-step answer:
We will start off by displaying Pascal's Triangle.
$
1 \\
1 - 1 \\
1 - 2 - 1 \\
1 - 3 - 3 - 1 \\
1 - 4 - 6 - 4 - 1 \\
1 - 5 - 10 - 10 - 5 - 1 \\
$
Now we can use this triangle to evaluate the coefficients of the expansion of the term $ {(a + b)^n} $ by taking the exponent $ n $ and then adding $ 1 $ . Here, the coefficients will correspond with the line $ n + 1 $ of the triangle.
Now if we compare the coefficients $ {(r + 3)^5} $ we know that here $ n = 5 $ so the coefficients of the expansion will correspond with the line $ 6 $ .
Here, the expansion follows the rule
$ {(a + b)^n} = {c_0}{a^n}{b^0} + {c_1}{a^{n - 1}}{b^1} + {c_{n - 1}}{a^1}{b^{n - 1}} + {c_n}{a^0}{b^n} $
Now, the values of the coefficients, from the triangle are,
$ 1 - 5 - 10 - 10 - 5 - 1 $
$ = 1{a^5}{b^0} + 5{a^4}b + 10{a^3}{b^2} + 10{a^2}{b^3} + 5a{b^4} + 1{a^0}{b^5} $
Now we will substitute the actual values of $ a,r $ and $ b $ into the expression.
$ = 1{(r)^5}{(3)^0} + 5{(r)^4}{(3)^1} + 10{(r)^3}{(3)^2} + 10{(r)^2}{(3)^3} + 5(r){(3)^4} $
Now, we will simplify the terms to evaluate the value.
$ = {r^5} + 15{r^4} + 90{r^3} + 270{r^2} + 405r + 243 $
Hence, the expansion of the expression $ {(r + 3)^5} $ is $ {r^5} + 15{r^4} + 90{r^3} + 270{r^2} + 405r + 243 $ .
Note: Pascal’s Triangle is a triangular array constructed by summing adjacent elements in preceding rows. It is a triangular array of the binomial coefficients that arises in probability theory, combinatorics and algebra. The rows of Pascal’s Triangle are conventionally enumerated starting with row $ n = 0 $ at the top. The entries in each row are numbered from the left beginning with $ k = 0 $ and are usually staggered relative to the numbers in the adjacent rows.
While converting orders do not matter for addition and multiplication. But order is important for subtraction and division. While comparing and substituting the values make sure to compare along with their signs.
Complete step-by-step answer:
We will start off by displaying Pascal's Triangle.
$
1 \\
1 - 1 \\
1 - 2 - 1 \\
1 - 3 - 3 - 1 \\
1 - 4 - 6 - 4 - 1 \\
1 - 5 - 10 - 10 - 5 - 1 \\
$
Now we can use this triangle to evaluate the coefficients of the expansion of the term $ {(a + b)^n} $ by taking the exponent $ n $ and then adding $ 1 $ . Here, the coefficients will correspond with the line $ n + 1 $ of the triangle.
Now if we compare the coefficients $ {(r + 3)^5} $ we know that here $ n = 5 $ so the coefficients of the expansion will correspond with the line $ 6 $ .
Here, the expansion follows the rule
$ {(a + b)^n} = {c_0}{a^n}{b^0} + {c_1}{a^{n - 1}}{b^1} + {c_{n - 1}}{a^1}{b^{n - 1}} + {c_n}{a^0}{b^n} $
Now, the values of the coefficients, from the triangle are,
$ 1 - 5 - 10 - 10 - 5 - 1 $
$ = 1{a^5}{b^0} + 5{a^4}b + 10{a^3}{b^2} + 10{a^2}{b^3} + 5a{b^4} + 1{a^0}{b^5} $
Now we will substitute the actual values of $ a,r $ and $ b $ into the expression.
$ = 1{(r)^5}{(3)^0} + 5{(r)^4}{(3)^1} + 10{(r)^3}{(3)^2} + 10{(r)^2}{(3)^3} + 5(r){(3)^4} $
Now, we will simplify the terms to evaluate the value.
$ = {r^5} + 15{r^4} + 90{r^3} + 270{r^2} + 405r + 243 $
Hence, the expansion of the expression $ {(r + 3)^5} $ is $ {r^5} + 15{r^4} + 90{r^3} + 270{r^2} + 405r + 243 $ .
Note: Pascal’s Triangle is a triangular array constructed by summing adjacent elements in preceding rows. It is a triangular array of the binomial coefficients that arises in probability theory, combinatorics and algebra. The rows of Pascal’s Triangle are conventionally enumerated starting with row $ n = 0 $ at the top. The entries in each row are numbered from the left beginning with $ k = 0 $ and are usually staggered relative to the numbers in the adjacent rows.
While converting orders do not matter for addition and multiplication. But order is important for subtraction and division. While comparing and substituting the values make sure to compare along with their signs.
Recently Updated Pages
Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

Discuss the various forms of bacteria class 11 biology CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

