
What is an example of an ideal gas law practice problem?
Answer
474.3k+ views
Hint: In order to solve this question, we will first understand the ideal gas law equation and each parameter involved in it and later we will use this ideal gas law equation to solve an example problem which can be set as an example for practice problems.
Complete step by step answer:
An equation which involves basic parameters of thermodynamics and governs the ideal gas behaviour is known as ideal gas equation and this is written as,
$PV = nRT$ where,
P is the pressure of the gas.
V is the volume of the gas.
n is the number of moles of the gas.
T is the temperature of the gas.
R is called universal gas constant and its value is fixed $R = 0.0821atmLmo{l^{ - 1}}{K^{ - 1}}$
Now, let us create an example for a practice problem.
Suppose an ideal gas is at a temperature of $303K$ having $2.5$ number of moles and volume $5L$ then calculate the amount of pressure of the gas.
So, this example has given to us that $T = 303K$ $n = 2.5$ $V = 5L$ and using ideal gas law equation,
$PV = nRT$ we can find pressure of the gas easily, on putting the value of parameters we get,
$P \times 5 = 2.5 \times 0.0821 \times 303$
or
$P = \dfrac{{62.19}}{5}$
$P = 12.4atm$ so, pressure of the gas is $12.4atm$
Hence, this was an example of a practice problem of the ideal gas law equation.
Note: It should be remembered that, the value of universal gas constant R is subject to units in which pressure, volume and temperature is measured such as if pressure is in units of Pascal and volume in cubic metres then value of universal gas constant R will be always check the units of each parameters and gas constant while solving such numerical practice problems on ideal gas law equation.
Complete step by step answer:
An equation which involves basic parameters of thermodynamics and governs the ideal gas behaviour is known as ideal gas equation and this is written as,
$PV = nRT$ where,
P is the pressure of the gas.
V is the volume of the gas.
n is the number of moles of the gas.
T is the temperature of the gas.
R is called universal gas constant and its value is fixed $R = 0.0821atmLmo{l^{ - 1}}{K^{ - 1}}$
Now, let us create an example for a practice problem.
Suppose an ideal gas is at a temperature of $303K$ having $2.5$ number of moles and volume $5L$ then calculate the amount of pressure of the gas.
So, this example has given to us that $T = 303K$ $n = 2.5$ $V = 5L$ and using ideal gas law equation,
$PV = nRT$ we can find pressure of the gas easily, on putting the value of parameters we get,
$P \times 5 = 2.5 \times 0.0821 \times 303$
or
$P = \dfrac{{62.19}}{5}$
$P = 12.4atm$ so, pressure of the gas is $12.4atm$
Hence, this was an example of a practice problem of the ideal gas law equation.
Note: It should be remembered that, the value of universal gas constant R is subject to units in which pressure, volume and temperature is measured such as if pressure is in units of Pascal and volume in cubic metres then value of universal gas constant R will be always check the units of each parameters and gas constant while solving such numerical practice problems on ideal gas law equation.
Recently Updated Pages
Master Class 12 Business Studies: Engaging Questions & Answers for Success

Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Chemistry: Engaging Questions & Answers for Success

Trending doubts
What is meant by exothermic and endothermic reactions class 11 chemistry CBSE

Which animal has three hearts class 11 biology CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

