Question

Every morning for breakfast, Mika drinks 20 cL of orange juice. How many milliliters of orange juice does she drink each day?

Answer 1

Hint: To answer this question, we need to know conversion of units topic in mathematics. We need to convert the given volume of juice from one unit to another. Here, it is given that Mika drinks 20 cL of orange juice and we need to convert this to mL. In order to do so, we multiply the given volume by 10 to obtain the answer.

Complete step by step solution:
The given question requires us to convert from one unit of volume to another unit of volume. Here in the question, it is given that Mila drinks 20 cL of orange juice. cL here stands for centilitres. Centi stands for 100. We have the following relation between litres and centilitres as,
$\Rightarrow 1\text{ }litre=100\text{ }centilitres$
We are required to convert the given volume of orange juice from the unit of cL to mL. Here, mL stands for millilitres. The relation between litres and millilitres is given as follows,
$\Rightarrow 1\text{ }litre=1000\text{ }millilitres$
Using the above two relations, we find a relation between millilitres and centilitres. Equate the right-hand side of both the above equations since the left-hand sides are the same,
$\Rightarrow 100\text{ }centilitres=1000\text{ }millilitres$
Dividing both sides of the equation by 100,
$\Rightarrow \dfrac{100}{100}\text{ }centilitres=\dfrac{1000}{100}\text{ }millilitres$
Cancelling out the terms,
$\Rightarrow 1\text{ }centilitre=10\text{ }millilitres$
This implies that every centilitre has 10 millilitres. Therefore, 20 centilitres have 20 times 10 millilitres.
$\Rightarrow 20\times 10mL$
Multiplying the two,
$\Rightarrow 200mL$

Hence, Mika drinks 200 millilitres or 200 mL of orange juice every day.

Note: Knowledge in unit conversions topic is essential to solve such questions. The units here in consideration are of volume. We can also solve this question directly by using the relation between centilitres and millilitres instead of finding their individual relationships with a litre and equating them.