Evaluate the following pattern and provide step by step solution about how the pattern works. Also find out the next four steps of this pattern.
$1 \times 8 + 1 = 9$
$12 \times 8 + 2 = 98$
$123 \times 8 + 3 = 987$
$1234 \times 8 + 4 = 9876$
$12345 \times + 5 = 98765$
Answer
593.4k+ views
Hint: First we will study the pattern carefully .By checking the left side we will find an increment in the digits. Using logic we will find out that the first term is 1 and in the second term 11+1=12 and this pattern continues such that in the last term it Is $11111 + 1111 + 111 + 11 + 1 = 12345$.
Complete step by step solution:
We can write $1 \times 8 + 1$as
$1 \times 8 + 1 = $\[\left( {1 \times {{10}^{1 - 1}}} \right) \times 8 + 1 = 9\]
Similarly we can write
$12 \times 8 + 2 = (11 + 1) \times 8 + 2$
\[ = \left( {1 \times {{10}^{2 - 1}} + 2 \times {{10}^{2 - 2}}} \right) \times 8 + 2 = 98\]
In this step we can write
$123 \times 8 + 3 = (111 + 11 + 1) \times 8 + 3$
=\[ = \left( {1 \times {{10}^{3 - 1}} + 2 \times {{10}^{3 - 2}} + 3 \times {{10}^{3 - 3}}} \right) \times 8 + 3 = 987\]
Similarly we write
$1234 \times 8 + 4 = (1111 + 111 + 11 + 1) \times 8 + 4$
\[ = \left( {1 \times {{10}^{4 - 1}} + 2 \times {{10}^{4 - 2}} + 3 \times {{10}^{4 - 3}} + 4 \times {{10}^{4 - 4}}} \right) \times 8 + 4 = 9876\]
We write
$12345 \times 8 + 5 = (11111 + 1111 + 111 + 11 + 1) \times 8 + 5$
\[ = \left( {1 \times {{10}^{5 - 1}} + 2 \times {{10}^{5 - 2}} + 3 \times {{10}^{5 - 3}} + 4 \times {{10}^{5 - 4}} + 5 \times {{10}^{5 - 5}}} \right) \times 8 + 5 = 98765\]
So, observing the similarity of the pattern we can say that
\[\left( {1 \times {{10}^{n - 1}} + 2 \times {{10}^{n - 2}} + 3 \times {{10}^{n - 3}} + ................ + n \times {{10}^{n - n}}} \right) \times 8 + 5 = \left( {\sum\limits_{i = 1}^n {i \times {{10}^{n - i}}} } \right) \times 8 + n\]
Thus, following the similarity of the pattern we can write the next four steps
$123456 \times 8 + 6 = (111111 + 11111 + 1111 + 111 + 11 + 1) \times 8 + 6$$$ $$ \[ = \left( {1 \times {{10}^{6 - 1}} + 2 \times {{10}^{6 - 2}} + 3 \times {{10}^{6 - 3}} + ................ + 6 \times {{10}^{6 - 6}}} \right) \times 8 + 6 = 123456 \times 8 + 6 = 987654\]
Similarly in next step
$1234567 \times 8 + 7 = (1111111 + 111111 + 11111 + 1111 + 111 + 11 + 1) \times 8 + 7 = 9876543$
In the next step
$12345678 \times 8 + 8 = (11111111 + 1111111 + 111111 + 11111 + 1111 + 111 + 11 + 1) \times 8 + 8 = 98765432$
Similarly we can write in the next step
$123456789 \times 8 + 9 = (111111111 + 11111111 + 1111111 + 111111 + 11111 + 1111 + 111 + 11 + 1) \times 8 + 9 = 987654321$
Thus we can find the next four steps.
Note: In Mathematics, number patterns are the patterns in which the numbers follow a certain similarity or common relationship. Example: $1,5,10,15, \ldots $in this pattern every term is multiple of $5$. The first task is to find the common similarity among the terms.
Complete step by step solution:
We can write $1 \times 8 + 1$as
$1 \times 8 + 1 = $\[\left( {1 \times {{10}^{1 - 1}}} \right) \times 8 + 1 = 9\]
Similarly we can write
$12 \times 8 + 2 = (11 + 1) \times 8 + 2$
\[ = \left( {1 \times {{10}^{2 - 1}} + 2 \times {{10}^{2 - 2}}} \right) \times 8 + 2 = 98\]
In this step we can write
$123 \times 8 + 3 = (111 + 11 + 1) \times 8 + 3$
=\[ = \left( {1 \times {{10}^{3 - 1}} + 2 \times {{10}^{3 - 2}} + 3 \times {{10}^{3 - 3}}} \right) \times 8 + 3 = 987\]
Similarly we write
$1234 \times 8 + 4 = (1111 + 111 + 11 + 1) \times 8 + 4$
\[ = \left( {1 \times {{10}^{4 - 1}} + 2 \times {{10}^{4 - 2}} + 3 \times {{10}^{4 - 3}} + 4 \times {{10}^{4 - 4}}} \right) \times 8 + 4 = 9876\]
We write
$12345 \times 8 + 5 = (11111 + 1111 + 111 + 11 + 1) \times 8 + 5$
\[ = \left( {1 \times {{10}^{5 - 1}} + 2 \times {{10}^{5 - 2}} + 3 \times {{10}^{5 - 3}} + 4 \times {{10}^{5 - 4}} + 5 \times {{10}^{5 - 5}}} \right) \times 8 + 5 = 98765\]
So, observing the similarity of the pattern we can say that
\[\left( {1 \times {{10}^{n - 1}} + 2 \times {{10}^{n - 2}} + 3 \times {{10}^{n - 3}} + ................ + n \times {{10}^{n - n}}} \right) \times 8 + 5 = \left( {\sum\limits_{i = 1}^n {i \times {{10}^{n - i}}} } \right) \times 8 + n\]
Thus, following the similarity of the pattern we can write the next four steps
$123456 \times 8 + 6 = (111111 + 11111 + 1111 + 111 + 11 + 1) \times 8 + 6$$$ $$ \[ = \left( {1 \times {{10}^{6 - 1}} + 2 \times {{10}^{6 - 2}} + 3 \times {{10}^{6 - 3}} + ................ + 6 \times {{10}^{6 - 6}}} \right) \times 8 + 6 = 123456 \times 8 + 6 = 987654\]
Similarly in next step
$1234567 \times 8 + 7 = (1111111 + 111111 + 11111 + 1111 + 111 + 11 + 1) \times 8 + 7 = 9876543$
In the next step
$12345678 \times 8 + 8 = (11111111 + 1111111 + 111111 + 11111 + 1111 + 111 + 11 + 1) \times 8 + 8 = 98765432$
Similarly we can write in the next step
$123456789 \times 8 + 9 = (111111111 + 11111111 + 1111111 + 111111 + 11111 + 1111 + 111 + 11 + 1) \times 8 + 9 = 987654321$
Thus we can find the next four steps.
Note: In Mathematics, number patterns are the patterns in which the numbers follow a certain similarity or common relationship. Example: $1,5,10,15, \ldots $in this pattern every term is multiple of $5$. The first task is to find the common similarity among the terms.
Recently Updated Pages
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred

Master Class 8 Social Science: Engaging Questions & Answers for Success

Master Class 8 Science: Engaging Questions & Answers for Success

Master Class 8 Maths: Engaging Questions & Answers for Success

Class 8 Question and Answer - Your Ultimate Solutions Guide

Master Class 9 Social Science: Engaging Questions & Answers for Success

Trending doubts
What is BLO What is the full form of BLO class 8 social science CBSE

Give me the opposite gender of Duck class 8 english CBSE

Citizens of India can vote at the age of A 18 years class 8 social science CBSE

Advantages and disadvantages of science

Full form of STD, ISD and PCO

Right to vote is a AFundamental Right BFundamental class 8 social science CBSE


