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How do you evaluate $ {\log _{15}}\left( {15} \right)? $

Answer
VerifiedVerified
532.8k+ views
Hint: As we know that the logarithm is the inverse function to exponentiation. That means the logarithm of a given number $ x $ is the exponent to which another fixed number, the base b, must be raised , to produce that number $ x $ . As per the definition of a logarithm $ {\log _a}b = c $ which gives that $ {a^c} = b $ . Here in the above expression the base is $ 15 $ . And we also have to assume that if no base $ b $ is written then the base is always 10. This is an example of base ten logarithm because $ 10 $ is the number that is raised to a power.

Complete step-by-step answer:
As per the given question we have $ {\log _{15}}\left( {15} \right) $ . We know that if
 $ {\log _a}b = x $ , then $ {a^x} = b $ .
Let us take $ {\log _{15}}\left( {15} \right) = x $ .
As we know that the inverse function of $ {\log _{15}}(z) = {15^z} $ and also it means that $ {\log _{15}}({15^z}) = z $ and also if there is $ {15^{{{\log }_{15}}(z)}} $ is equal to $ z $ .
So to here find the value of $ x $ , we need to get rid of the logarithm term, we will apply this rule, here $ z = 15 $ .
Therefore $ {15^{{{\log }_{15}}(15)}} = {15^x} $ , By applying the above rule we can write
 $ \Rightarrow 15 = {15^x} $ .
It gives us $ {15^1} = {15^x}
\Rightarrow x = 1 $ .
Hence the value of $ {\log _{15}}\left( {15} \right) = 1 $ .
So, the correct answer is “1”.

Note: We should always be careful while solving logarithm formulas and before solving this kind of problems we should know all the rules of logarithm and exponentiation. We have to keep in mind that when a logarithm is written without any base, like this: $ \log 100 $ then this usually means that the base is already there which is $ 10 $ . It is called a common logarithm or decadic logarithm, is the logarithm to the base $ 10 $ . One way we can approach log problems is to keep in mind that $ {a^b} = c $ and $ {\log _a}c = b $ .