Question

How do you evaluate ${{10}^{2}}\div \left( 5\times 4 \right)+\left( 2\times 2 \right)?$

Answer 1

Hint: We will use the BODMAS rule to find the value of the given expression. We will first find the products inside the brackets. Then we will find the square. We will then do the operation division. Finally, we will add the terms.

Complete step by step solution:
Let us consider the given expression ${{10}^{2}}\div \left( 5\times 4 \right)+\left( 2\times 2 \right).$
We are asked to evaluate the given expression and to find the value.
We will use the BODMAS rule to find the value of the expression.
In the given expression, we will first find the product inside the brackets.
Here, we can see two pairs of brackets.
So, we will get the products $5\times 4=20$ and $2\times 2=4.$
Now, we will consider the terms with exponents.
There is only one term that has an exponent. That is, ${{10}^{2}}.$
We know that we will multiply a term the exponent times.
So, we will get ${{10}^{2}}=10\times 10=100.$
The next operation we will do is the division.
As we can see, there is only one division symbol in the given expression.
We will divide $100$ by $20.$
When we divide $100$ by $20,$ we will get $\dfrac{100}{20}=5.$
Now, we have only $5,4$ and $+$ in the expression. So, we will add $5$ to $4.$
We will get $5+4=9.$
Hence the value of the given expression is $9.$

Note: We know that the BODMAS rule shows the order in which we do the operations on a given expression. The first letter B implies that we should consider the brackets first. The O in the rule stands for order. That means, the exponents. The letter D stands for division, M stands for multiplication, A stands for addition and S stands for subtraction.