Evaluate $1 + 2x + 3{x^2} + 4{x^3} + ........$ up to infinite, where $\left| x \right| < 1.$
Answer
598.2k+ views
Hint: It is given in the question that we have to Evaluate $1 + 2x + 3{x^2} + 4{x^3} + ........$ up to infinite, where $\left| x \right| < 1$ .
Let, $S = 1 + 2x + 3{x^2} + 4{x^3} + ........$ (I)
Then, multiply S by x.
Thus, subtract the equation of xS from the equation of S.
This will give a Geometric progression i.e. GP.
Hence, we will get the required answer on solving the equation further.
Complete step-by-step answer:
It is given in the question that we have to Evaluate $1 + 2x + 3{x^2} + 4{x^3} + ........$ up to infinite, where $\left| x \right| < 1$ .
Let, $S = 1 + 2x + 3{x^2} + 4{x^3} + ........$ (I)
Now, multiply S by x, we get,
$\therefore xS = x\left( {1 + 2x + 3{x^2} + 4{x^3} + ........} \right)$
$\therefore xS = x + 2{x^2} + 3{x^3}........$ (II)
Now, subtract equation (I) with equation (II), we get,
\[\therefore \left( {S = 1 + 2x + 3{x^2} + 4{x^3} + ........} \right) - \left( {xS = x + 2{x^2} + 3{x^3}.......} \right)\] .
\[\therefore S - xS = \left( {1 + 2x + 3{x^2} + 4{x^3} + ........} \right) - \left( {x + 2{x^2} + 3{x^3}.......} \right)\] .
\[\therefore S = \dfrac{1}{{{{\left( {1 - x} \right)}^2}}}\] \[\therefore S\left( {1 - x} \right) = 1 + x + {x^2} + {x^3} + ........\]
Note: Arithmetic Progression: An Arithmetic Progression (AP) or arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant. Difference here means second minus first. For instance, the sequence 5,7,9,11,13,15,17,…is an arithmetic progression with a common difference of 2.
General formula of Arithmetic Progression (AP) is ${a_n} = {a_m} + \left( {n - m} \right)d$
Geometric Progression: A geometric Progression, also known as geometric sequence, is a sequence of numbers where each term after the first is found by multiplying the previous one by a fixed number called the common ratio.
For example: the sequence 2,6,18,54,….is a geometric progression with common ratio 3.
General formula of Geometric Progression (GP) is $a,ar,a{r^2},a{r^3},a{r^4},.......$ where $r \ne 1$ is the common ratio and ‘a’ is a scalar factor.
Arithmetic-Geometric Progression: An Arithmetic-Geometric Progression (AGP) is a progression in which each term can be represented as the product of the terms of an Arithmetic Progression (AP) and Geometric Progression (GP).
Let, $S = 1 + 2x + 3{x^2} + 4{x^3} + ........$ (I)
Then, multiply S by x.
Thus, subtract the equation of xS from the equation of S.
This will give a Geometric progression i.e. GP.
Hence, we will get the required answer on solving the equation further.
Complete step-by-step answer:
It is given in the question that we have to Evaluate $1 + 2x + 3{x^2} + 4{x^3} + ........$ up to infinite, where $\left| x \right| < 1$ .
Let, $S = 1 + 2x + 3{x^2} + 4{x^3} + ........$ (I)
Now, multiply S by x, we get,
$\therefore xS = x\left( {1 + 2x + 3{x^2} + 4{x^3} + ........} \right)$
$\therefore xS = x + 2{x^2} + 3{x^3}........$ (II)
Now, subtract equation (I) with equation (II), we get,
\[\therefore \left( {S = 1 + 2x + 3{x^2} + 4{x^3} + ........} \right) - \left( {xS = x + 2{x^2} + 3{x^3}.......} \right)\] .
\[\therefore S - xS = \left( {1 + 2x + 3{x^2} + 4{x^3} + ........} \right) - \left( {x + 2{x^2} + 3{x^3}.......} \right)\] .
\[\therefore S = \dfrac{1}{{{{\left( {1 - x} \right)}^2}}}\] \[\therefore S\left( {1 - x} \right) = 1 + x + {x^2} + {x^3} + ........\]
Note: Arithmetic Progression: An Arithmetic Progression (AP) or arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant. Difference here means second minus first. For instance, the sequence 5,7,9,11,13,15,17,…is an arithmetic progression with a common difference of 2.
General formula of Arithmetic Progression (AP) is ${a_n} = {a_m} + \left( {n - m} \right)d$
Geometric Progression: A geometric Progression, also known as geometric sequence, is a sequence of numbers where each term after the first is found by multiplying the previous one by a fixed number called the common ratio.
For example: the sequence 2,6,18,54,….is a geometric progression with common ratio 3.
General formula of Geometric Progression (GP) is $a,ar,a{r^2},a{r^3},a{r^4},.......$ where $r \ne 1$ is the common ratio and ‘a’ is a scalar factor.
Arithmetic-Geometric Progression: An Arithmetic-Geometric Progression (AGP) is a progression in which each term can be represented as the product of the terms of an Arithmetic Progression (AP) and Geometric Progression (GP).
Recently Updated Pages
Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Chemistry: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

State and prove Bernoullis theorem class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

Discuss the various forms of bacteria class 11 biology CBSE

