Question

# Ethylamine reacts with nitrous acid to form:A. methyl alcoholB. ethyl alcoholC. ethaneD. ethyl nitrite

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Hint: Ethylamine is a primary amine which belongs to a class of organic compound containing amine functional group. They act as bases when treated with an acid.

Ethylamine is a one carbon homologue of the simplest primary amine methylamine in the family of amine organic compounds. They contain a $- N{H_2}$ group which is basic in nature. It has the ability to accept protons from a proton donor.
Nitrous acid is an acid which only exists in the solution phase. The formula of nitrous acid is$HN{O_2}$ . It is very effective and used in the preparation of diazonium salts. Actually the reaction of an amine with nitrous acid ($HO - N = O$ ) is used to identify the presence of primary, secondary or tertiary amines as each of them react in a different way with nitrous acid.
Nitrous acid is unstable intermediate and is prepared instantly before the preparation of diazonium salt. For this a cold and dilute solution of hydrochloric acid ($HCl$ ) is treated with a solution of sodium nitrite ($NaN{O_2}$) at a temperature of $0 - 5^\circ C$.
$NaN{O_2} + HCI \to NaCI + HN{O_2}\;$
$C{H_3}C{H_2}N{H_2}\xrightarrow{{NaN{O_2} + HCl}}\left[ {C{H_3}C{H_2}{N^ + }C{l^ - }} \right]\xrightarrow{{{H_2}O}}C{H_3}C{H_2}OH + {N_2} + HCl$
Ethane is a hydrocarbon with chemical formula $C2H6$ . It is not formed under the given reaction conditions. Ethyl nitrate is $C{H_3}C{H_2}N{O_2}$ is not formed in this reaction as it is not a displacement reaction.