Ethanol has a higher boiling point than diethyl ether or ethylamine. Why ?
Answer
497.4k+ views
Hint: Intermolecular forces are the forces that exist between molecules. The greater the boiling point, the stronger the intermolecular force between the molecules. H-bonding exists in ethanol, but not in diethyl ether (because the O-atom is connected to the C-atom), and the H-bonds created by the n-atom in ethyl amine are weaker than those formed by the O-atom.
Complete answer:
The hydroxyl group is a highly polar functional group found in alcohols. As a result, the $ OH $ group's oxygen draws the $ OH $ bond's shared electron pair towards itself.
As a result, the $ OH $ group's oxygen has a partial negative charge, while hydrogen has a partial positive charge.
One molecule's negative oxygen interacts with another's positive hydrogen. Hydrogen bonding is the name for this type of interaction. As a result, a high number of alcohol molecules are firmly linked.
As a result, a significant amount of energy must be supplied to dissolve this connection. As a result, the boiling points of alcohol are greater.
This form of hydrogen bonding does not exist in ethers. As a result of the decreased intermolecular interaction, ethers boil at lower temperatures.
Because of this, ethanol has a higher boiling point than diethyl ether.
Note:
To answer these questions, you'll need to understand intermolecular forces of attraction like hydrogen bonding, Vander wall forces, and others. Ionic bonds $ > $ Hydrogen bonds $ > $ Van der Waals dipole-dipole interactions $ > $ Van Der Waals dispersion forces are the relative strengths of the bonding forces.
Complete answer:
The hydroxyl group is a highly polar functional group found in alcohols. As a result, the $ OH $ group's oxygen draws the $ OH $ bond's shared electron pair towards itself.
As a result, the $ OH $ group's oxygen has a partial negative charge, while hydrogen has a partial positive charge.
One molecule's negative oxygen interacts with another's positive hydrogen. Hydrogen bonding is the name for this type of interaction. As a result, a high number of alcohol molecules are firmly linked.
As a result, a significant amount of energy must be supplied to dissolve this connection. As a result, the boiling points of alcohol are greater.
This form of hydrogen bonding does not exist in ethers. As a result of the decreased intermolecular interaction, ethers boil at lower temperatures.
Because of this, ethanol has a higher boiling point than diethyl ether.
Note:
To answer these questions, you'll need to understand intermolecular forces of attraction like hydrogen bonding, Vander wall forces, and others. Ionic bonds $ > $ Hydrogen bonds $ > $ Van der Waals dipole-dipole interactions $ > $ Van Der Waals dispersion forces are the relative strengths of the bonding forces.
Recently Updated Pages
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

State and prove Bernoullis theorem class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Discuss the various forms of bacteria class 11 biology CBSE

