Question

What is the equivalent weight of silver nitrate?

Answer 1

Hint: The mass of an element that combines with 1 gram of hydrogen, 8.0 gram of oxygen, or 35.5 gram of chlorine at STP is its equivalent weight. These values are equal to the molecule's atomic weight divided by the valence of the atom present in the molecule.

Complete answer:
\[AgN{O_3}\] is the chemical formula for silver nitrate, an inorganic substance. The gram atomic weight of an element is divided by its valence to get its equivalent weight (combining power).
The equivalent weight of silver nitrate \[(AgN{O_3})\] is $170$
Explanation:
Silver nitrate \[(AgN{O_3})\] has the molecular formula. If we look at the chemical equation for the creation of silver nitrate, we can see that:
$A{g^ + } + N{O^{3 - }} \to AgN{O_3}$
The formula for a chemical equation is the division of the molecular weight and total charge on the positive side.
The molar mass of silver in \[AgN{O_3}\] is \[108\] .
Nitrogen's molar mass = $14$
Oxygen has a molar mass of = \[16\] .
$ \Rightarrow 16 \times 3 = 48$
Then,
$AgN{O_3} = 108 + 14 + 48 = 170$
As a result, the equivalent weight of \[AgN{O_3}\] is as follows:
$\dfrac{{170}}{1} = 170$

Additional Information:
Silver nitrate is made by reacting silver (such as silver bullion or silver foil) with nitric acid, which produces silver nitrate, water, and nitrogen oxides. The amount of nitric acid employed determines the reaction by-products.
\[
  3Ag + 4HN{O_3}(Cold\,and\,diluted) \to 3AgN{O_3} + 2{H_2}O + NO \\
  Ag + 2HN{O_3}\left( {hot\,and\,concentrated\,} \right) \to AgN{O_3} + {H_2}O + N{O_2} \\
 \]
Because of the hazardous nitrogen oxides produced during the reaction, this is done in a fume hood.

Note:
To cauterise diseased tissues around a skin wound, silver nitrate topical (for use on the skin) is utilised. Silver nitrate can also help stop bleeding from a minor skin wound by forming a scab. Warts and skin tags can also be removed with silver nitrate.