What is the equivalent weight of $KMn{O_4}$ in acidic, basic and neutral medium?
Answer
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Hint: ${K^ + }$ and $Mn{O^ - }$ make up potassium permanganate, an inorganic compound with the chemical formula $KMn{O_4}$. It's a dark-purple crystalline salt that dissolves in water to produce intensely pink or purple solutions.
Complete answer:
Equivalent weight (also known as the gramme equivalent) is the mass of one equivalent is the mass of a given substance that can combine with or displace a specified quantity of another substance.
Molar mass of a compound is divided by its valence (combining power) to obtain its equivalent weight.
The formula to find the equivalent weight is given by
$EquivalentWeight = \dfrac{{MolarMass}}{{NumberOfElectronsGained\left( {or} \right)Lost}}$
We know that the molecular mass of potassium permanganate, $KMn{O_4} = 158.04g$
The equivalent weight of potassium permanganate in an acidic medium:
$MnO_4^ - + 8H + 5{e^ - } \to M{n_2} + 4{H_2}O$
Here, $n = 5$ as the number of electrons gained is equal to $5$
potassium permanganate acts as an oxidizer in an acidic medium
$EquivalentWeight = \dfrac{{158.04}}{5} = 31.61g$ per equivalent
The equivalent weight of potassium permanganate in a basic medium:
$MnO_4^ - + 2{H_2}O + 3{e^ - } \to Mn{O_2} + 4O{H^ - }$
Here, $n = 3$ as the number of electrons gained is equal to $3$
$EquivalentWeight = \dfrac{{158.04}}{3} = 52.68g$ per equivalent
The equivalent weight of potassium permanganate in a neutral medium:
The equivalent weight of potassium permanganate in neutral medium is equal to the equivalent weight of potassium permanganate in a basic medium
$EquivalentWeight = \dfrac{{158.04}}{3} = 52.68g$ per equivalent
Therefore, the equivalent weight of $KMn{O_4}$ in acidic medium $ = 31.61g$ per equivalent, basic medium $ = 52.68g$ per equivalent and neutral medium $ = 52.68g$ per equivalent.
Note:
Potassium permanganate is used as a wet dressing on blistered or oozing pus wounds on the skin's surface. Athlete's foot and impetigo are two conditions that can affect athletes. Athlete's foot and impetigo are examples of bacterial and fungal skin infections that potassium permanganate can help cure.
Complete answer:
Equivalent weight (also known as the gramme equivalent) is the mass of one equivalent is the mass of a given substance that can combine with or displace a specified quantity of another substance.
Molar mass of a compound is divided by its valence (combining power) to obtain its equivalent weight.
The formula to find the equivalent weight is given by
$EquivalentWeight = \dfrac{{MolarMass}}{{NumberOfElectronsGained\left( {or} \right)Lost}}$
We know that the molecular mass of potassium permanganate, $KMn{O_4} = 158.04g$
The equivalent weight of potassium permanganate in an acidic medium:
$MnO_4^ - + 8H + 5{e^ - } \to M{n_2} + 4{H_2}O$
Here, $n = 5$ as the number of electrons gained is equal to $5$
potassium permanganate acts as an oxidizer in an acidic medium
$EquivalentWeight = \dfrac{{158.04}}{5} = 31.61g$ per equivalent
The equivalent weight of potassium permanganate in a basic medium:
$MnO_4^ - + 2{H_2}O + 3{e^ - } \to Mn{O_2} + 4O{H^ - }$
Here, $n = 3$ as the number of electrons gained is equal to $3$
$EquivalentWeight = \dfrac{{158.04}}{3} = 52.68g$ per equivalent
The equivalent weight of potassium permanganate in a neutral medium:
The equivalent weight of potassium permanganate in neutral medium is equal to the equivalent weight of potassium permanganate in a basic medium
$EquivalentWeight = \dfrac{{158.04}}{3} = 52.68g$ per equivalent
Therefore, the equivalent weight of $KMn{O_4}$ in acidic medium $ = 31.61g$ per equivalent, basic medium $ = 52.68g$ per equivalent and neutral medium $ = 52.68g$ per equivalent.
Note:
Potassium permanganate is used as a wet dressing on blistered or oozing pus wounds on the skin's surface. Athlete's foot and impetigo are two conditions that can affect athletes. Athlete's foot and impetigo are examples of bacterial and fungal skin infections that potassium permanganate can help cure.
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