What is the equivalent resistance of the circuit?
A. \[20\]ohms
B. \[10\]ohms
C. \[5\]ohms
D. \[2\text{ }\]ohms
Answer
621k+ views
Hint: The total resistances of resistors series is the sum of their individual resistance and the total resistance of resistors in parallel are is the sum of the reciprocal of their resistance.
Formula used:
For two resistors \[{{R}_{1}}\] and \[{{R}_{2}}\] is series, total resistance R is given by
\[R={{R}_{1}}+{{R}_{2}}\]
For two resistors \[{{R}_{1}}\] and \[{{R}_{2}}\] is parallel, total resistance R is given by
\[\frac{1}{R}=\frac{1}{{{R}_{1}}}+\frac{1}{{{R}_{2}}}\]
Complete step by step solution:
The given circuit is a parallel circuit containing two branches. In one branch, there is a \[6\text{ }\Omega \] and a \[\text{4 }\Omega \] resistor, and in the other branch there are two \[\text{5 }\Omega \]-resistors.
In the circuit, the \[6\text{ }\Omega \]-resistor is in series with the \[\text{4 }\Omega \]-resistor and the two \[\text{5 }\Omega \] resistors are in series with each other.
So the equivalent resistance in one branch (containing \[6\text{ }\Omega \] and \[\text{4 }\Omega \] resistor) is:
\[{{R}_{1}}=4\text{ }\Omega +\text{6 }\Omega =10\text{ }\Omega \]
The equivalent resistance in the other branch (containing two \[\text{5 }\Omega \]-resistors) is
\[{{R}_{2}}=5\text{ }\Omega +5\text{ }\Omega =10\text{ }\Omega \]
Therefore, \[{{R}_{1}}\] and \[{{R}_{2}}\] is parallel, so, equivalent resistance R of the circuit is given by
\[\begin{align}
& \frac{1}{R}=\frac{1}{{{R}_{1}}}+\frac{1}{{{R}_{2}}} \\
& \frac{1}{R}=\frac{1}{10\text{ }\Omega }+\frac{1}{10\text{ }\Omega } \\
& \frac{1}{R}=\frac{2}{10\text{ }\Omega } \\
& R=5\text{ }\Omega \\
\end{align}\]
So, option C is the correct answer.
Additional information:
It is convenient to connect electrical components in parallel, as when disconnecting one component the other components are not switched off.
Note: In a parallel circuit, the voltage across each component is the same, but the current through each branch is different. The total current is equal to the sum of currents in individual branches. The equivalent resistance of the circuit is less than the equivalent resistance in each branch. The total resistance will decrease with addition of more components.
In a series connection, the components are connected in one single branch, back to back, and the current through each component is the same, whereas the voltage across each component is different.
Formula used:
For two resistors \[{{R}_{1}}\] and \[{{R}_{2}}\] is series, total resistance R is given by
\[R={{R}_{1}}+{{R}_{2}}\]
For two resistors \[{{R}_{1}}\] and \[{{R}_{2}}\] is parallel, total resistance R is given by
\[\frac{1}{R}=\frac{1}{{{R}_{1}}}+\frac{1}{{{R}_{2}}}\]
Complete step by step solution:
The given circuit is a parallel circuit containing two branches. In one branch, there is a \[6\text{ }\Omega \] and a \[\text{4 }\Omega \] resistor, and in the other branch there are two \[\text{5 }\Omega \]-resistors.
In the circuit, the \[6\text{ }\Omega \]-resistor is in series with the \[\text{4 }\Omega \]-resistor and the two \[\text{5 }\Omega \] resistors are in series with each other.
So the equivalent resistance in one branch (containing \[6\text{ }\Omega \] and \[\text{4 }\Omega \] resistor) is:
\[{{R}_{1}}=4\text{ }\Omega +\text{6 }\Omega =10\text{ }\Omega \]
The equivalent resistance in the other branch (containing two \[\text{5 }\Omega \]-resistors) is
\[{{R}_{2}}=5\text{ }\Omega +5\text{ }\Omega =10\text{ }\Omega \]
Therefore, \[{{R}_{1}}\] and \[{{R}_{2}}\] is parallel, so, equivalent resistance R of the circuit is given by
\[\begin{align}
& \frac{1}{R}=\frac{1}{{{R}_{1}}}+\frac{1}{{{R}_{2}}} \\
& \frac{1}{R}=\frac{1}{10\text{ }\Omega }+\frac{1}{10\text{ }\Omega } \\
& \frac{1}{R}=\frac{2}{10\text{ }\Omega } \\
& R=5\text{ }\Omega \\
\end{align}\]
So, option C is the correct answer.
Additional information:
It is convenient to connect electrical components in parallel, as when disconnecting one component the other components are not switched off.
Note: In a parallel circuit, the voltage across each component is the same, but the current through each branch is different. The total current is equal to the sum of currents in individual branches. The equivalent resistance of the circuit is less than the equivalent resistance in each branch. The total resistance will decrease with addition of more components.
In a series connection, the components are connected in one single branch, back to back, and the current through each component is the same, whereas the voltage across each component is different.
Recently Updated Pages
Master Class 12 Economics: Engaging Questions & Answers for Success

Master Class 12 English: Engaging Questions & Answers for Success

Master Class 12 Social Science: Engaging Questions & Answers for Success

Master Class 12 Maths: Engaging Questions & Answers for Success

Master Class 12 Physics: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

Find the value of the expression given below sin 30circ class 11 maths CBSE

Two of the body parts which do not appear in MRI are class 11 biology CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

