What is the equation for the base ionization constant of $ RbOH $ ?
Answer
541.5k+ views
Hint: Ionization is the mechanism by which an atom or molecule gains or loses electrons, often in conjunction with other chemical modifications, to gain or lose a negative or positive charge. An ion is the electrically charged atom or molecule that results.
Complete step by step answer:
The inorganic compound $ RbOH $ stands for rubidium hydroxide. It's a colorless solid that can be purchased as aqueous solutions. Rubidium hydroxide, like other strong bases, is extremely corrosive. Bases can be weak or strong, depending on the degree of ionization.
In the aqueous solution, a strong base ionizes entirely. In water, these compounds ionize, yielding one or more hydroxide ions $ \left( {O{H^ - }} \right) $ per base molecule. Stable compounds are formed when strong bases react with strong acids. Soluble metal hydroxide compounds, like potassium hydroxide, are the most common strong bases. Some metal hydroxides are weaker simply due to their inability to dissolve.
The ionization equation of $ RbOH $ , can be written as
$ RbOH\left( {aq} \right) \to R{b^ + }\left( {aq} \right) + O{H^ - }\left( {aq} \right) $
The base ionization constant, $ {K_b} $ , can be written as follows from the equation:
$ {K_b} = \dfrac{{\left[ {R{b^ + }} \right]\left[ {O{H^ - }} \right]}}{{RbOH}} $
The strength of the base is reflected in the numerical value of $ {K_b} $ . The stronger the base, the higher the value of $ {K_b} $ , and vice versa.
So, the answer is $ {K_b} = \dfrac{{\left[ {R{b^ + }} \right]\left[ {O{H^ - }} \right]}}{{RbOH}} $ .
Additional Information:
In contrast, a weak base ionizes just slightly in an aqueous solution. Keep in mind that a base is a material that absorbs a hydrogen ion from another substance. When a weak base like ammonia dissolves in water, it accepts an $ {H^ + } $ ion from the environment, forming the hydroxide ion and the base's conjugate acid, the ammonium ion.
Note:
The alkali metal bases are more potent than the less soluble alkaline earth metal bases. Since the conjugate acid of a strong base is very weak, conclude that the reverse reaction does not occur when writing out the dissociation equation of a strong base.
Complete step by step answer:
The inorganic compound $ RbOH $ stands for rubidium hydroxide. It's a colorless solid that can be purchased as aqueous solutions. Rubidium hydroxide, like other strong bases, is extremely corrosive. Bases can be weak or strong, depending on the degree of ionization.
In the aqueous solution, a strong base ionizes entirely. In water, these compounds ionize, yielding one or more hydroxide ions $ \left( {O{H^ - }} \right) $ per base molecule. Stable compounds are formed when strong bases react with strong acids. Soluble metal hydroxide compounds, like potassium hydroxide, are the most common strong bases. Some metal hydroxides are weaker simply due to their inability to dissolve.
The ionization equation of $ RbOH $ , can be written as
$ RbOH\left( {aq} \right) \to R{b^ + }\left( {aq} \right) + O{H^ - }\left( {aq} \right) $
The base ionization constant, $ {K_b} $ , can be written as follows from the equation:
$ {K_b} = \dfrac{{\left[ {R{b^ + }} \right]\left[ {O{H^ - }} \right]}}{{RbOH}} $
The strength of the base is reflected in the numerical value of $ {K_b} $ . The stronger the base, the higher the value of $ {K_b} $ , and vice versa.
So, the answer is $ {K_b} = \dfrac{{\left[ {R{b^ + }} \right]\left[ {O{H^ - }} \right]}}{{RbOH}} $ .
Additional Information:
In contrast, a weak base ionizes just slightly in an aqueous solution. Keep in mind that a base is a material that absorbs a hydrogen ion from another substance. When a weak base like ammonia dissolves in water, it accepts an $ {H^ + } $ ion from the environment, forming the hydroxide ion and the base's conjugate acid, the ammonium ion.
Note:
The alkali metal bases are more potent than the less soluble alkaline earth metal bases. Since the conjugate acid of a strong base is very weak, conclude that the reverse reaction does not occur when writing out the dissociation equation of a strong base.
Recently Updated Pages
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

State and prove Bernoullis theorem class 11 physics CBSE

Draw a diagram of a plant cell and label at least eight class 11 biology CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

Discuss the various forms of bacteria class 11 biology CBSE

