
Elevation in boiling point was \[{0.52^o}C\] when \[6g\] of compound X was dissolved in \[100g\] of water. Molecular mass of the compound M in \[gmo{l^{ - 1}}\] is: (\[{K_b}\] for water is \[0.52K{m^{ - 1}}\].)
A.\[120\]
B.\[60\]
C.\[600\]
D.\[180\]
Answer
485.1k+ views
Hint: We need to know that the elevation in boiling point explains the method that the boiling point of a liquid will be more by adding another compound. The molecular mass of the compound can be found by using the equation of elevation of boiling point. The amount of solute is directly proportional to the amount of change in boiling point. The boiling point of solution is always higher than that of the solvent and it takes place by adding non – volatile solute like salt to the pure solvent like water.
Complete answer:
As we know that the molecular mass of the compound is not equal to \[120\]. Hence, option (A) is incorrect.
The molecular mass of the compound can be find out by using the equation of elevation of boiling point and that is,
\[\Delta {T_b} = {K_b}m\]
Where, \[{T_b}\] is the boiling point temperature and \[{K_b}\] is equal to the proportionality constant and m is equal to the molar mass of the solvent and the equation is also written as,
$\Delta {T_b} = {K_b} \times \dfrac{{\text{Mass Of Solute}}}{{\text{Molar Mass Of Solute} \times \text{Mass Of Solvent}\left( {ing} \right)}} \times 1000$
Mass of solute is equal to \[6g\]and mass of solvent is equal to \[100g\]. Substituting the given values in the above equation will get the molecular mass of the compound.
$0.52 = 0.52 \times \dfrac{6}{{M \times 100}} \times 1000$
By rearranging the equation,
\[M = 60gmo{l^{ - 1}}\]
Therefore, the molecular mass of the compound is equal to \[60gmo{l^{ - 1}}\].
The molecular mass of the compound is not equal to \[600\]. Hence, option (C) is incorrect.
The molecular mass of the compound is not equal to \[180\]. Hence, option (D) is incorrect.
Hence, option (B) is correct.
Note:
We need to remember that the molecular mass of the compound is found by using the equation of elevation of boiling point. The boiling point elevation represents the increase in the boiling point of a solvent by adding a solute. The vapour pressure of the solvent will be less by adding the solute and it takes place due to the displacement of the molecule of solvent by the solute.
Complete answer:
As we know that the molecular mass of the compound is not equal to \[120\]. Hence, option (A) is incorrect.
The molecular mass of the compound can be find out by using the equation of elevation of boiling point and that is,
\[\Delta {T_b} = {K_b}m\]
Where, \[{T_b}\] is the boiling point temperature and \[{K_b}\] is equal to the proportionality constant and m is equal to the molar mass of the solvent and the equation is also written as,
$\Delta {T_b} = {K_b} \times \dfrac{{\text{Mass Of Solute}}}{{\text{Molar Mass Of Solute} \times \text{Mass Of Solvent}\left( {ing} \right)}} \times 1000$
Mass of solute is equal to \[6g\]and mass of solvent is equal to \[100g\]. Substituting the given values in the above equation will get the molecular mass of the compound.
$0.52 = 0.52 \times \dfrac{6}{{M \times 100}} \times 1000$
By rearranging the equation,
\[M = 60gmo{l^{ - 1}}\]
Therefore, the molecular mass of the compound is equal to \[60gmo{l^{ - 1}}\].
The molecular mass of the compound is not equal to \[600\]. Hence, option (C) is incorrect.
The molecular mass of the compound is not equal to \[180\]. Hence, option (D) is incorrect.
Hence, option (B) is correct.
Note:
We need to remember that the molecular mass of the compound is found by using the equation of elevation of boiling point. The boiling point elevation represents the increase in the boiling point of a solvent by adding a solute. The vapour pressure of the solvent will be less by adding the solute and it takes place due to the displacement of the molecule of solvent by the solute.
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

