Question

What is the electronic configuration of \[M{{n}^{3+}}\] ?

Answer 1

Hint: The electronic configuration is nothing but how electrons are distributed. It tells us how electrons are distributed in different atomic orbitals.

Complete step by step answer:
According to the modern electronic configuration which shows that different atoms are arranged in different orbitals or shells. The modern electronic configuration or just electronic configuration starts from the very first shell which is the ‘s’ shell and then ‘p’ ‘d’ ‘f’ and so on.
The standard notation of the electronic configuration yields a lengthy configuration for the higher atoms having higher atomic number and due to that reason we often use abbreviated configuration in which the configuration of the nearest noble gas takes the place of the symbol of that gas which makes it easy to read and write. Also it makes it easy to understand and easy to grasp.
Electron configuration helps to determine the valency of an atom, predict it’s properties in which group or period that particular atom will belong to and whom will it resemble to, also to interpret it’s atomic spectra.
Manganese has an atomic number of $25$ and $M{{n}^{3+}}$ will be $22$ since it will give three electrons. Atoms generally give or take up electrons to attain more stability by attaining noble gas configuration.
The electronic configuration of $M{{n}^{3+}}$ will be $[Ar]3{{d}^{5}}4{{s}^{2}}$

Note: The electronic configuration written above is abbreviated one for the unabbreviated electron configuration you can simply replace Ar that is argon’s symbol by it’s electronic configuration which will be long and have more chances to mistake.