Question

What is the electron configuration of Platinum?

Answer 1

Hint: We know that Atomic number of an element is equal to the number of protons in the nucleus. The platinum is \[5d\] transition metal and it is a group \[VII\] element. The \[5d\] transition series has a lanthanide series in it. Thus the general electronic configuration for the \[5d\] transition element.

Complete answer:
The atomic number of an element is equal to the number of protons in the nucleus. In other words, the atomic number is a unique property of an element. Platinum is found in the middle of the periodic table. It is a group \[VII\] element. It is a transition metal. It is a neighbor to the other elements like iridium, osmium, palladium, and ruthenium. Platinum is present in the sixth period. The sixth-period elements are the transition metal atom. This is called the transition metal as the valence electron or last shell electrons enter the d-subshell.
The \[5d\] transition series starts with the lanthanum elements and ends on the mercury. Platinum is present in the \[5d\] transition series. Since it is a \[5d\] transition series, the valence or the last shell electron enters into the \[5d\] orbital. We are interested in determining the atomic number of the platinum. Platinum is present in group \[VII\] , thus its last shell configuration.
Platinum atoms have \[~78\] electrons.
The electronic configuration of platinum \[~pt\] is
\[1{{s}^{2~}}2{{s}^{2}}~2{{p}^{6}}~3{{s}^{2}}~3{{p}^{6~}}4{{s}^{2}}~3{{d}^{10}}~4{{p}^{6}}~5{{s}^{2}}~4{{d}^{10~}}5{{p}^{6~}}6{{s}^{1}}~4{{f}^{14}}~5{{d}^{9}}~\] or $\left[ Xe \right]6{{s}^{1}}~4{{f}^{14}}~5{{d}^{9}}$

Note:
Remember that Platinum is a precious metal and represented with the platinum symbol, Pt. The word Platinum comes from the Spanish word "Platina." Platina means Silver. It is one of the rarest elements found in the earth's crust with an estimated abundance of \[5\text{ }\mu g/kg.\] Platinum can conduct electricity.