Draw the Newmann projection formula for different conformations of ethane.
Answer
Verified
456.6k+ views
Hint: Conformational isomerism is related to rotation about sigma bonds, and has no connection with the differences in the connectivity of the atoms or geometry of bonding.
Complete answer:
In ethane (HC-CH), the two carbon atoms are linked to each other by a single covalent bond. The remaining three valencies are satisfied by hydrogen atoms. If we keep the position of one carbon atom fixed and allow the other carbon to rotate about the covalent bond, an infinite number of relative arrangements (or conformations) of the hydrogen atoms attached to the two carbon atoms will be possible. Out of these, the two important conformations are staggered and eclipsed. These are described as follows:
(a)Staggered conformation. In this conformation, the rotation about the C-C bond is such that the hydrogen atoms attached tetrahedrally to the two carbon atoms are completely staggered i.e. they are at maximum distance apart in space.
(b) Eclipsed conformation. In this case, the rotation about the C-C bond is such that the hydrogen atoms attached tetrahedrally to one carbon atom completely cover or eclipse the hydrogen atoms attached to the other carbon atom. The staggered and eclipsed conformations of ethane are represented with the help of space models (3D or three dimensional representations) called saw horse models.
Note: We know that a sigma bond between the two carbon atoms is formed as a result of the axial overlap of the two sp. hybrid orbitals. The electron distribution in the molecular orbital thus formed is cylindrically symmetrical around the internuclear axis. As a result, free rotation of the atoms or groups attached tetrahedrally to the carbon atoms is possible. This will lead to a number of different relative arrangements of the atoms or groups in space. These different relative spatial arrangements which arise because of rotation around the single bond are called conformations or rotational isomers or rotamers.
Complete answer:
In ethane (HC-CH), the two carbon atoms are linked to each other by a single covalent bond. The remaining three valencies are satisfied by hydrogen atoms. If we keep the position of one carbon atom fixed and allow the other carbon to rotate about the covalent bond, an infinite number of relative arrangements (or conformations) of the hydrogen atoms attached to the two carbon atoms will be possible. Out of these, the two important conformations are staggered and eclipsed. These are described as follows:
(a)Staggered conformation. In this conformation, the rotation about the C-C bond is such that the hydrogen atoms attached tetrahedrally to the two carbon atoms are completely staggered i.e. they are at maximum distance apart in space.
(b) Eclipsed conformation. In this case, the rotation about the C-C bond is such that the hydrogen atoms attached tetrahedrally to one carbon atom completely cover or eclipse the hydrogen atoms attached to the other carbon atom. The staggered and eclipsed conformations of ethane are represented with the help of space models (3D or three dimensional representations) called saw horse models.
Note: We know that a sigma bond between the two carbon atoms is formed as a result of the axial overlap of the two sp. hybrid orbitals. The electron distribution in the molecular orbital thus formed is cylindrically symmetrical around the internuclear axis. As a result, free rotation of the atoms or groups attached tetrahedrally to the carbon atoms is possible. This will lead to a number of different relative arrangements of the atoms or groups in space. These different relative spatial arrangements which arise because of rotation around the single bond are called conformations or rotational isomers or rotamers.
Recently Updated Pages
Master Class 11 English: Engaging Questions & Answers for Success
Master Class 11 Computer Science: Engaging Questions & Answers for Success
Master Class 11 Maths: Engaging Questions & Answers for Success
Master Class 11 Social Science: Engaging Questions & Answers for Success
Master Class 11 Economics: Engaging Questions & Answers for Success
Master Class 11 Business Studies: Engaging Questions & Answers for Success
Trending doubts
10 examples of friction in our daily life
What problem did Carter face when he reached the mummy class 11 english CBSE
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE
Difference Between Prokaryotic Cells and Eukaryotic Cells
State and prove Bernoullis theorem class 11 physics CBSE
The sequence of spore production in Puccinia wheat class 11 biology CBSE