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# Draw rough sketches for  $\Delta XYZ$ such that YL is an altitude in the exterior of the triangle.

Last updated date: 11th Sep 2024
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Answer
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Hint: We can draw an altitude in the exterior of a triangle only if it is an obtuse angled triangle. By using this concept we draw the triangle first and then altitude to the exterior of a triangle.

Complete step by step solution:
We have to draw an altitude in the exterior of the  $\Delta XYZ$
An altitude can be drawn in the exterior of a triangle only if it is an obtuse angled triangle.
So, we need to draw  $\Delta XYZ$ as an obtuse angled triangle as shown in the figure.
Altitude (perpendicular line).
$YL =$ exterior altitude of  $\Delta XYZ$ .
Here,
In figure,  $\Delta XYZ$ is obtuse angled triangle because we can only draw an exterior altitude from abuse angle it can observed that on  $\Delta XYZ,YZ$ is an altitude drawn interior to side  $XZ$ which is extends up to point  $L.$

Note: To know whether the altitude will be on the exterior of a triangle or in the interior of a triangle, we need to know the properties of the triangle.
For an acute angled triangle, the altitude will be in the interior of a triangle.
For a right angled triangle, the altitude will be at the angle which is right angled.