Draw a graph for the following table and identify the variation.
\[x\] 2 3 5 8 10 \[y\] 8 12 20 32 40
Hence, find the value of \[y\] when \[x=4\].
| \[x\] | 2 | 3 | 5 | 8 | 10 |
| \[y\] | 8 | 12 | 20 | 32 | 40 |
Answer
608.1k+ views
Hint:we will use the variation table to first draw the graph helping us to determine the equation of the line. from the equation we will find the value of which we need to find later on.
Complete step by step solution:
From the given table we can deduce that as \[x\] increases the value of \[y\] also increases. Also notice that the value of \[y\] is increasing in a systematic manner. Thus, we will check by the most simple variation….
Let \[y=\text{K}x\].
\[\dfrac{y}{x}=\text{K}\]
Where K is the constant of probability.
Thus, from the given values ,we can deduce that
\[\text{K=}\dfrac{y}{x}=\dfrac{8}{2}=\dfrac{12}{3}=\dfrac{20}{5}=\dfrac{32}{8}=\dfrac{40}{10}=\dfrac{4}{1}\]
Thus, we get the relation \[y=4x\] easily which is similar to an equation of a straight line. So we will compare this equation with the general equation of straight line which is
\[y=mx+c\,\,\,\,\,\text{ }\!\![\!\!\text{ where }m\,\,\text{is slope and }c\,\text{is }y-\operatorname{int}ercept\text{ }\!\!]\!\!\text{ }\].
And we get the values….
\[m=4\,\,\,\,\text{and }c=0\]
From this we know that slope is 4. And since the slope is positive it will constantly move upward.
We can say that the line does not intersect with \[y\]-axis since it does not have a \[y\]-intercept.
And thus the plotting can now be done with the points (2,8)(3,12)(5,20)(8,32)(10,40) we got from the variation table.
Moreover, by putting the value \[x=4\] in the equation \[y=4x\] We get the value of \[y\] as 16. Therefore , the point is (4,16).
The line will pass from the origin(0,0).
Note: if the equation would have been more complex , such as, having a constant term as well \[y=kx+L\text{ }\!\![\!\!\text{ L is a constant variable }\!\!]\!\!\text{ }\], then we would have also be given more factors from the question to determine what the value of this constant term could have been. Also make sure to plot the points given from the variation carefully.
Complete step by step solution:
From the given table we can deduce that as \[x\] increases the value of \[y\] also increases. Also notice that the value of \[y\] is increasing in a systematic manner. Thus, we will check by the most simple variation….
Let \[y=\text{K}x\].
\[\dfrac{y}{x}=\text{K}\]
Where K is the constant of probability.
Thus, from the given values ,we can deduce that
\[\text{K=}\dfrac{y}{x}=\dfrac{8}{2}=\dfrac{12}{3}=\dfrac{20}{5}=\dfrac{32}{8}=\dfrac{40}{10}=\dfrac{4}{1}\]
Thus, we get the relation \[y=4x\] easily which is similar to an equation of a straight line. So we will compare this equation with the general equation of straight line which is
\[y=mx+c\,\,\,\,\,\text{ }\!\![\!\!\text{ where }m\,\,\text{is slope and }c\,\text{is }y-\operatorname{int}ercept\text{ }\!\!]\!\!\text{ }\].
And we get the values….
\[m=4\,\,\,\,\text{and }c=0\]
From this we know that slope is 4. And since the slope is positive it will constantly move upward.
We can say that the line does not intersect with \[y\]-axis since it does not have a \[y\]-intercept.
And thus the plotting can now be done with the points (2,8)(3,12)(5,20)(8,32)(10,40) we got from the variation table.
Moreover, by putting the value \[x=4\] in the equation \[y=4x\] We get the value of \[y\] as 16. Therefore , the point is (4,16).
The line will pass from the origin(0,0).
Note: if the equation would have been more complex , such as, having a constant term as well \[y=kx+L\text{ }\!\![\!\!\text{ L is a constant variable }\!\!]\!\!\text{ }\], then we would have also be given more factors from the question to determine what the value of this constant term could have been. Also make sure to plot the points given from the variation carefully.
Recently Updated Pages
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred

Master Class 9 Social Science: Engaging Questions & Answers for Success

Master Class 9 Science: Engaging Questions & Answers for Success

Master Class 9 Maths: Engaging Questions & Answers for Success

Master Class 9 General Knowledge: Engaging Questions & Answers for Success

Class 9 Question and Answer - Your Ultimate Solutions Guide

Trending doubts
What is the Full Form of ISI and RAW

Who is eligible for RTE class 9 social science CBSE

Which are the Top 10 Largest States of India?

Write the 6 fundamental rights of India and explain in detail

What is the Full Form of ICSE / ISC ?

On an outline map of India mark the Karakoram range class 9 social science CBSE

