
What does the mean value theorem mean?
Answer
535.8k+ views
Hint: Mean value theorem is the part of differentiation concept in calculus. This is a very important result. You have to know differentiation before knowing this. This result is very important and it has many important applications.
Complete step by step solution:
According to the mean value theorem, for a function f which is continuous in an closed interval and also differentiable in an open interval, then there will always be a value c which exits in the interval such that the differentiation of f at c that is f'(c) is always equal to the average rate of change in the interval.
For example, we will take a question. How do you determine all values of c that satisfy the mean value theorem on the interval [0, 1] for $ f\left( x \right)=\dfrac{x}{x+6}$ . This can be solved by doing,
$ f\left( x \right)=\dfrac{x}{x+6}$--- ( 1 )
The derivative of f(x) :
$ \Rightarrow {{f}^{'}}\left( x \right)=\dfrac{6}{{{\left( x+6 \right)}^{2}}}$ ------(2)
According to mean value theorem, we get
$\Rightarrow {{f}^{'}}\left( x \right)=\dfrac{f\left( 1 \right)-f\left( 0 \right)}{1-0} $------(3)
$ \Rightarrow f\left( 1 \right)=\dfrac{1}{1+6}=\dfrac{1}{7}$ ------ (4)
$ \Rightarrow f\left( 0 \right)=\dfrac{0}{0+6}=0$ ------(5)
We have to substitute 4 and 5. After substituting, we get:
$\Rightarrow {{f}^{'}}\left( x \right)=\dfrac{\dfrac{1}{7}-0}{1-0}=\dfrac{1}{7}$
We have to equate 2 and 5. Therefore, we get:
$ \Rightarrow \dfrac{6}{{{\left( x+6 \right)}^{2}}}=\dfrac{1}{7}$
$ \Rightarrow {\left( x+6 \right)}^{2}=42$
$ \Rightarrow { x+6}=\pm{6.480741}$
$ \Rightarrow { x+6}=+{6.480741} \Rightarrow { x}={0.480741}$
$ \Rightarrow { x+6}=-{6.480741} \Rightarrow { x}={-12.480741 }$
The answers are x = 0.480741 and x = -12.480741. Only x = 0.480741 can be found in the range [0,1]. So, it is the only c that satisfies the mean value theorem.
Note: The theorem can be understood by doing some examples. So, it is important that you do some problems relating to this theorem. You have to do the sums step by step like shown in the above example so that you can understand it easily.
Complete step by step solution:
According to the mean value theorem, for a function f which is continuous in an closed interval and also differentiable in an open interval, then there will always be a value c which exits in the interval such that the differentiation of f at c that is f'(c) is always equal to the average rate of change in the interval.
For example, we will take a question. How do you determine all values of c that satisfy the mean value theorem on the interval [0, 1] for $ f\left( x \right)=\dfrac{x}{x+6}$ . This can be solved by doing,
$ f\left( x \right)=\dfrac{x}{x+6}$--- ( 1 )
The derivative of f(x) :
$ \Rightarrow {{f}^{'}}\left( x \right)=\dfrac{6}{{{\left( x+6 \right)}^{2}}}$ ------(2)
According to mean value theorem, we get
$\Rightarrow {{f}^{'}}\left( x \right)=\dfrac{f\left( 1 \right)-f\left( 0 \right)}{1-0} $------(3)
$ \Rightarrow f\left( 1 \right)=\dfrac{1}{1+6}=\dfrac{1}{7}$ ------ (4)
$ \Rightarrow f\left( 0 \right)=\dfrac{0}{0+6}=0$ ------(5)
We have to substitute 4 and 5. After substituting, we get:
$\Rightarrow {{f}^{'}}\left( x \right)=\dfrac{\dfrac{1}{7}-0}{1-0}=\dfrac{1}{7}$
We have to equate 2 and 5. Therefore, we get:
$ \Rightarrow \dfrac{6}{{{\left( x+6 \right)}^{2}}}=\dfrac{1}{7}$
$ \Rightarrow {\left( x+6 \right)}^{2}=42$
$ \Rightarrow { x+6}=\pm{6.480741}$
$ \Rightarrow { x+6}=+{6.480741} \Rightarrow { x}={0.480741}$
$ \Rightarrow { x+6}=-{6.480741} \Rightarrow { x}={-12.480741 }$
The answers are x = 0.480741 and x = -12.480741. Only x = 0.480741 can be found in the range [0,1]. So, it is the only c that satisfies the mean value theorem.
Note: The theorem can be understood by doing some examples. So, it is important that you do some problems relating to this theorem. You have to do the sums step by step like shown in the above example so that you can understand it easily.
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
What is meant by exothermic and endothermic reactions class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

What are Quantum numbers Explain the quantum number class 11 chemistry CBSE

