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How does the location of hydrogen on the periodic table differ from other nonmetals?

Answer
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Hint: hydrogen is a nonmetal and is put above the group in the periodic table since it has \[n{s^1}\] electron design like the alkali metals. Notwithstanding, it changes extraordinarily from the alkali metals as it forms cations \[\left( {{H^ + }} \right)\] more hesitantly than the other alkali metals.
Since hydrogen is a nonmetal and structures \[{H^ - }\] (hydride anions), it is now and then positioned above the halogen in the periodic table. Hydrogen also forms \[{H_2}\] dihydrogen like halogen. In any case, hydrogen is totally different from the halogen

Complete step by step answer:
One manner it could 'attempt' to acquire an electron as any element from the halogen group \[\left( {F - Cl - Br...} \right)\] would do.
Then again, it could lose its one electron, where case it would have a place with the alkali metals \[\left( {Li - Na - K...} \right).\]
Practically speaking,\[\;H\] generally shares its electron, either by covalent bonds, or by donating an electron and cooperating with\[\;{H_2}O\] to frame the \[{H_3}O + {\text{ }}or{\text{ }}'acid'\] particle. So, H is too uncommon to even consider placing it in a specific Group.
It's unique, since it has just a single electron, while the ideal "noble gas" setup (helium) would call for two.

Note: Hydrogen has a much smaller electron affinity than halogens. \[{H_2}\] dihydrogen or atomic hydrogen is non-polar with two electrons. There are weak attractive forces between \[{H_2}\] molecules, bringing about low boiling and melting points. Be that as it may, \[{H_2}\] has solid intramolecular forces; \[{H_2}\] reaction are for the most part delayed at room temperature because of the solid\[\;H--H{\text{ }}bond.\] \[{H_2}\] is handily activated by heat, irradiation, or catalysis. Initiated hydrogen gas reacts rapidly and exothermically with numerous substances.