What does average rate of change mean?
Answer
570.9k+ views
Hint: We have to first describe the conditions for the average rate of change. We take an arbitrary function and find its two inputs and the outputs for those particular inputs. We find the difference or change in the values and then find the average rate of change as $ \dfrac{\Delta y}{\Delta x}=\dfrac{{{y}_{2}}-{{y}_{1}}}{{{x}_{2}}-{{x}_{1}}}=\dfrac{f\left( {{x}_{2}} \right)-f\left( {{x}_{1}} \right)}{{{x}_{2}}-{{x}_{1}}} $ .
Complete step by step solution:
A rate of change describes how an output quantity changes relative to the change in the input quantity. The units on a rate of change are output units per input units.
Let us take a function $ y=f\left( x \right) $ . We have two values of $ x $ as $ x={{x}_{1}},{{x}_{2}} $ and for those values of $ x $ we have two values of $ y $ where $ {{y}_{1}}=f\left( {{x}_{1}} \right) $ and $ {{y}_{2}}=f\left( {{x}_{2}} \right) $ .
We find the change of values for $ x $ and $ y $ .
Therefore, $ \Delta x={{x}_{2}}-{{x}_{1}} $ and $ \Delta y={{y}_{2}}-{{y}_{1}} $ .
The average rate of change will be denoted by $ \dfrac{\Delta y}{\Delta x}=\dfrac{{{y}_{2}}-{{y}_{1}}}{{{x}_{2}}-{{x}_{1}}}=\dfrac{f\left( {{x}_{2}} \right)-f\left( {{x}_{1}} \right)}{{{x}_{2}}-{{x}_{1}}} $ .
Obviously, the function is not a perfect straight line and it will change differently inside that interval but the average rate can only evaluate the change between the two given points not at each individual point.
Note: A decrease is expressed by a negative change or “negative increase.” A rate of change is negative when the output decreases as the input increases or when the output increases as the input decreases.
Complete step by step solution:
A rate of change describes how an output quantity changes relative to the change in the input quantity. The units on a rate of change are output units per input units.
Let us take a function $ y=f\left( x \right) $ . We have two values of $ x $ as $ x={{x}_{1}},{{x}_{2}} $ and for those values of $ x $ we have two values of $ y $ where $ {{y}_{1}}=f\left( {{x}_{1}} \right) $ and $ {{y}_{2}}=f\left( {{x}_{2}} \right) $ .
We find the change of values for $ x $ and $ y $ .
Therefore, $ \Delta x={{x}_{2}}-{{x}_{1}} $ and $ \Delta y={{y}_{2}}-{{y}_{1}} $ .
The average rate of change will be denoted by $ \dfrac{\Delta y}{\Delta x}=\dfrac{{{y}_{2}}-{{y}_{1}}}{{{x}_{2}}-{{x}_{1}}}=\dfrac{f\left( {{x}_{2}} \right)-f\left( {{x}_{1}} \right)}{{{x}_{2}}-{{x}_{1}}} $ .
Obviously, the function is not a perfect straight line and it will change differently inside that interval but the average rate can only evaluate the change between the two given points not at each individual point.
Note: A decrease is expressed by a negative change or “negative increase.” A rate of change is negative when the output decreases as the input increases or when the output increases as the input decreases.
Recently Updated Pages
Master Class 5 English: Engaging Questions & Answers for Success

Master Class 5 Maths: Engaging Questions & Answers for Success

Master Class 5 Social Science: Engaging Questions & Answers for Success

Master Class 5 Science: Engaging Questions & Answers for Success

Class 5 Question and Answer - Your Ultimate Solutions Guide

Master Class 9 General Knowledge: Engaging Questions & Answers for Success

Trending doubts
The total number of vertebrae in man is a30 b31 c32 class 12 biology CBSE

The number of cranial nerves in a frog is A 10 pairs class 12 biology CBSE

Differentiate between Pyramid of energy and pyramid class 12 biology CBSE

Antibodies present in colostrum which protect the new class 12 biology CBSE

How many pollen sacs theca are present in each lobe class 12 biology CBSE

Bolting ie internode elongation just prior to flowering class 12 biology CBSE

