Answer
Verified
414k+ views
Hint – We will first define the whole process of Roasting and the whole process of calcination and then in last we will discuss the difference between these two processes with examples.
Complete answer:
We know that Roasting and Calcination both are used in the conversion of ore into metal oxide.
Now, we will define both the processes.
Roasting may be defined as a process of heating the ore, below its melting point, in the excess supply of air. Following changes occur –
(i) Moisture is removed.
(ii) Volatile impurities of Sulphur, Arsenic and Phosphorus are removed as their volatile oxides.
${S_8} + 8{O_2} \to 8S{O_2} \uparrow $
${P_4} + 5{O_2} \to {P_4}{O_{10}}$
(iii) Sulphide ores are decomposed to metallic oxides.
$2PbS + 3{O_2} \to 2PbO + 2S{O_2} \uparrow $
Calcination may be defined as a process of heating the ore, below its melting point,
in the limited supply of air. Following changes occur –
(i) Moisture is removed.
(ii) Volatile impurities of Sulphur, Arsenic and Phosphorus are removed as their volatile oxides.
${S_8} + 8{O_2} \to 8S{O_2} \uparrow $
${P_4} + 5{O_2} \to {P_4}{O_{10}}$
(iii) Carbonates and hydroxides are decomposed to metallic oxides.
$
CaC{O_3} \to CaO + C{O_2} \uparrow \\
2Al{\left( {OH} \right)_3} \to A{l_2}{O_3} + 3{H_2}O \\
$
So, the difference between Roasting and Calcination is,
1. The process of Roasting is done by heating the ore in excess supply of air whereas the process of Calcination is done by heating the ore in limited supply of air.
2. In the process of roasting, sulphide ores are decomposed to form metallic oxides whereas in the process of calcination, carbonates and hydroxides are decomposed to metallic oxides.
3. Example of Roasting - $4As + 3{O_2} \to 2A{s_2}{O_3}$
Example of Calcination - $F{e_2}{O_3}.3{H_2}O \to F{e_2}{O_3} + 3{H_2}O$
Note – In these types of questions where we have to differentiate two processes, first we should know the definition and the whole process, only then we can differentiate the two processes. So, definitions and examples must be remembered.
Complete answer:
We know that Roasting and Calcination both are used in the conversion of ore into metal oxide.
Now, we will define both the processes.
Roasting may be defined as a process of heating the ore, below its melting point, in the excess supply of air. Following changes occur –
(i) Moisture is removed.
(ii) Volatile impurities of Sulphur, Arsenic and Phosphorus are removed as their volatile oxides.
${S_8} + 8{O_2} \to 8S{O_2} \uparrow $
${P_4} + 5{O_2} \to {P_4}{O_{10}}$
(iii) Sulphide ores are decomposed to metallic oxides.
$2PbS + 3{O_2} \to 2PbO + 2S{O_2} \uparrow $
Calcination may be defined as a process of heating the ore, below its melting point,
in the limited supply of air. Following changes occur –
(i) Moisture is removed.
(ii) Volatile impurities of Sulphur, Arsenic and Phosphorus are removed as their volatile oxides.
${S_8} + 8{O_2} \to 8S{O_2} \uparrow $
${P_4} + 5{O_2} \to {P_4}{O_{10}}$
(iii) Carbonates and hydroxides are decomposed to metallic oxides.
$
CaC{O_3} \to CaO + C{O_2} \uparrow \\
2Al{\left( {OH} \right)_3} \to A{l_2}{O_3} + 3{H_2}O \\
$
So, the difference between Roasting and Calcination is,
1. The process of Roasting is done by heating the ore in excess supply of air whereas the process of Calcination is done by heating the ore in limited supply of air.
2. In the process of roasting, sulphide ores are decomposed to form metallic oxides whereas in the process of calcination, carbonates and hydroxides are decomposed to metallic oxides.
3. Example of Roasting - $4As + 3{O_2} \to 2A{s_2}{O_3}$
Example of Calcination - $F{e_2}{O_3}.3{H_2}O \to F{e_2}{O_3} + 3{H_2}O$
Note – In these types of questions where we have to differentiate two processes, first we should know the definition and the whole process, only then we can differentiate the two processes. So, definitions and examples must be remembered.
Recently Updated Pages
Basicity of sulphurous acid and sulphuric acid are
Three beakers labelled as A B and C each containing 25 mL of water were taken A small amount of NaOH anhydrous CuSO4 and NaCl were added to the beakers A B and C respectively It was observed that there was an increase in the temperature of the solutions contained in beakers A and B whereas in case of beaker C the temperature of the solution falls Which one of the following statements isarecorrect i In beakers A and B exothermic process has occurred ii In beakers A and B endothermic process has occurred iii In beaker C exothermic process has occurred iv In beaker C endothermic process has occurred
What is the stopping potential when the metal with class 12 physics JEE_Main
The momentum of a photon is 2 times 10 16gm cmsec Its class 12 physics JEE_Main
How do you arrange NH4 + BF3 H2O C2H2 in increasing class 11 chemistry CBSE
Is H mCT and q mCT the same thing If so which is more class 11 chemistry CBSE
Trending doubts
Difference between Prokaryotic cell and Eukaryotic class 11 biology CBSE
Difference Between Plant Cell and Animal Cell
Select the word that is correctly spelled a Twelveth class 10 english CBSE
Fill the blanks with the suitable prepositions 1 The class 9 english CBSE
What is the z value for a 90 95 and 99 percent confidence class 11 maths CBSE
Give 10 examples for herbs , shrubs , climbers , creepers
What organs are located on the left side of your body class 11 biology CBSE
What is BLO What is the full form of BLO class 8 social science CBSE
Change the following sentences into negative and interrogative class 10 english CBSE