
Determine the number of atoms in a mole of ${\text{Ca}}{\left( {{\text{OH}}} \right)_{\text{2}}}$.
A. $30\, \times \,6.02 \times {10^{23}}$ atoms
B. $5 \times \,6.02 \times {10^{23}}$ atoms
C. $6\, \times \,6.02 \times {10^{23}}$ atoms
D. None of these
Answer
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Hint: According to the Avogadro, one mole of any substance has $\,6.02 \times {10^{23}}$ atoms, ions or molecules. This number $\,6.02 \times {10^{23}}$ is known as Avogadro number.
Complete step by step answer:
First, determine the number of atoms in one mole of calcium hydroxide and then multiply the number of atoms with the Avogadro number to determine the total number of atoms in a mole.
${\text{Ca}}{\left( {{\text{OH}}} \right)_{\text{2}}}$ is a compound. A compound is a substance made up of two or more different types of elements.
${\text{Ca}}{\left( {{\text{OH}}} \right)_{\text{2}}}$ is made up of three types of elements. Calcium, hydrogen and oxygen.
So, each molecule of ${\text{Ca}}{\left( {{\text{OH}}} \right)_{\text{2}}}$ has a total of five atoms, one of calcium, two of oxygen and two of hydrogen.
Each atom of ${\text{Ca}}{\left( {{\text{OH}}} \right)_{\text{2}}}$ has$\,6.02 \times {10^{23}}$atoms per mole.
So, the element of ${\text{Ca}}{\left( {{\text{OH}}} \right)_{\text{2}}}$ will have,
$\,6.02 \times {10^{23}}$atoms per mole.
Therefore, a mole of ${\text{Ca}}{\left( {{\text{OH}}} \right)_{\text{2}}}$ has $\,5 \times 6.02 \times {10^{23}}$ atoms.
Therefore the option (B) is correct.
Additional information: In the same manner, the number of ions can also be determined. As the given ${\text{Ca}}{\left( {{\text{OH}}} \right)_{\text{2}}}$ has three types of ions, one calcium and two hydroxide ions.
${\text{Ca}}{\left( {{\text{OH}}} \right)_{\text{2}}}\, \to {\text{C}}{{\text{a}}^{{\text{2 + }}}}{\text{ + }}\,{\text{2}}\,{\text{O}}{{\text{H}}^{\text{ - }}}$
So, the total number of ions will be $3\, \times \,6.02 \times {10^{23}}$ ions.
Note:
The number of atoms present in $12\,{\text{g}}$ of carbon-12 is known as one mole. The total number of atoms is the sum of all the atoms of a compound. The subscript after the bracket represents the numbers of atoms that are present within the bracket. The superscript represents the charge of an ion not the number of that ion.
Complete step by step answer:
First, determine the number of atoms in one mole of calcium hydroxide and then multiply the number of atoms with the Avogadro number to determine the total number of atoms in a mole.
${\text{Ca}}{\left( {{\text{OH}}} \right)_{\text{2}}}$ is a compound. A compound is a substance made up of two or more different types of elements.
${\text{Ca}}{\left( {{\text{OH}}} \right)_{\text{2}}}$ is made up of three types of elements. Calcium, hydrogen and oxygen.
So, each molecule of ${\text{Ca}}{\left( {{\text{OH}}} \right)_{\text{2}}}$ has a total of five atoms, one of calcium, two of oxygen and two of hydrogen.
Each atom of ${\text{Ca}}{\left( {{\text{OH}}} \right)_{\text{2}}}$ has$\,6.02 \times {10^{23}}$atoms per mole.
So, the element of ${\text{Ca}}{\left( {{\text{OH}}} \right)_{\text{2}}}$ will have,
$\,6.02 \times {10^{23}}$atoms per mole.
Therefore, a mole of ${\text{Ca}}{\left( {{\text{OH}}} \right)_{\text{2}}}$ has $\,5 \times 6.02 \times {10^{23}}$ atoms.
Therefore the option (B) is correct.
Additional information: In the same manner, the number of ions can also be determined. As the given ${\text{Ca}}{\left( {{\text{OH}}} \right)_{\text{2}}}$ has three types of ions, one calcium and two hydroxide ions.
${\text{Ca}}{\left( {{\text{OH}}} \right)_{\text{2}}}\, \to {\text{C}}{{\text{a}}^{{\text{2 + }}}}{\text{ + }}\,{\text{2}}\,{\text{O}}{{\text{H}}^{\text{ - }}}$
So, the total number of ions will be $3\, \times \,6.02 \times {10^{23}}$ ions.
Note:
The number of atoms present in $12\,{\text{g}}$ of carbon-12 is known as one mole. The total number of atoms is the sum of all the atoms of a compound. The subscript after the bracket represents the numbers of atoms that are present within the bracket. The superscript represents the charge of an ion not the number of that ion.
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