
How do you determine if $5y+3x=1$ is parallel, perpendicular to neither to the line $y+10x=-3$ ?
Answer
547.5k+ views
Hint: Firstly, here we find the slope for both the given linear line equations. Let us then name it ${{m}_{1}},{{m}_{2}}$ . To find if they are parallel to each other, then check for the condition, ${{m}_{1}}={{m}_{2}}$ . To check if they are perpendicular to each other, then check for the condition, ${{m}_{1}}{{m}_{2}}=-1$ .By checking out these two conditions we shall know if both the lines are parallel or perpendicular or neither.
Complete step by step answer:
The given line equations are, $5y+3x=1;y+10x=-3$
To check if a pair of lines are parallel or perpendicular or neither we must first find their slopes.
Any straight line can be written in slope-intercept form, $y=mx+c$
Where $m$ is said to be the slope of the line $\left( m=\tan \theta \right)$
And $c$ is the y-intercept.
Now writing the first equation in slope-intercept form to find the slope.
$\Rightarrow 5y+3x=1$
$\Rightarrow 5y=1-3x$
Now isolate the $y$ variable.
$\Rightarrow y=\dfrac{1-3x}{5}$
Now separate the terms.
$\Rightarrow y=\dfrac{1}{5}-\dfrac{3x}{5}$
Comparing it with the slope-equation, $y=mx+b$
$\Rightarrow {{m}_{1}}=\dfrac{-3}{5};b=\dfrac{1}{5}$
Now writing the second equation in slope-intercept form to find the slope.
$\Rightarrow y+10x=-3$
Now isolate the $y$ variable.
$\Rightarrow y=-3-10x$
Comparing it with the slope-equation, $y=mx+b$
$\Rightarrow {{m}_{2}}=-10;b=-3$
Now To check if a pair of lines are parallel, their slopes must be equal ${{m}_{1}}={{m}_{2}}$
Here ${{m}_{1}}=\dfrac{-3}{5};{{m}_{2}}=-10$
Since they are not equal, they are not parallel.
Now to check if a pair of lines are perpendicular, they should satisfy the condition, ${{m}_{1}}{{m}_{2}}=-1$
${{m}_{1}}=\dfrac{-3}{5};{{m}_{2}}=-10$
$\Rightarrow {{m}_{1}}{{m}_{2}}=\dfrac{-3}{5}\times -10=6$
$\Rightarrow 6\ne 1$
Since the slopes did not satisfy the condition, they are not perpendicular.
Hence the lines are not parallel and not perpendicular.
Note:
The slope of a line is the steepness of a line in a horizontal or vertical direction. The slope of a line can be calculated by taking the ratio of the change in vertical dimensions upon the change in horizontal dimensions which is given by,
The formula for finding slope when two points are given is,$m=\dfrac{\left( {{y}_{2}}-{{y}_{1}} \right)}{\left( {{x}_{2}}-{{x}_{1}} \right)}$
Complete step by step answer:
The given line equations are, $5y+3x=1;y+10x=-3$
To check if a pair of lines are parallel or perpendicular or neither we must first find their slopes.
Any straight line can be written in slope-intercept form, $y=mx+c$
Where $m$ is said to be the slope of the line $\left( m=\tan \theta \right)$
And $c$ is the y-intercept.
Now writing the first equation in slope-intercept form to find the slope.
$\Rightarrow 5y+3x=1$
$\Rightarrow 5y=1-3x$
Now isolate the $y$ variable.
$\Rightarrow y=\dfrac{1-3x}{5}$
Now separate the terms.
$\Rightarrow y=\dfrac{1}{5}-\dfrac{3x}{5}$
Comparing it with the slope-equation, $y=mx+b$
$\Rightarrow {{m}_{1}}=\dfrac{-3}{5};b=\dfrac{1}{5}$
Now writing the second equation in slope-intercept form to find the slope.
$\Rightarrow y+10x=-3$
Now isolate the $y$ variable.
$\Rightarrow y=-3-10x$
Comparing it with the slope-equation, $y=mx+b$
$\Rightarrow {{m}_{2}}=-10;b=-3$
Now To check if a pair of lines are parallel, their slopes must be equal ${{m}_{1}}={{m}_{2}}$
Here ${{m}_{1}}=\dfrac{-3}{5};{{m}_{2}}=-10$
Since they are not equal, they are not parallel.
Now to check if a pair of lines are perpendicular, they should satisfy the condition, ${{m}_{1}}{{m}_{2}}=-1$
${{m}_{1}}=\dfrac{-3}{5};{{m}_{2}}=-10$
$\Rightarrow {{m}_{1}}{{m}_{2}}=\dfrac{-3}{5}\times -10=6$
$\Rightarrow 6\ne 1$
Since the slopes did not satisfy the condition, they are not perpendicular.
Hence the lines are not parallel and not perpendicular.
Note:
The slope of a line is the steepness of a line in a horizontal or vertical direction. The slope of a line can be calculated by taking the ratio of the change in vertical dimensions upon the change in horizontal dimensions which is given by,
The formula for finding slope when two points are given is,$m=\dfrac{\left( {{y}_{2}}-{{y}_{1}} \right)}{\left( {{x}_{2}}-{{x}_{1}} \right)}$
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