
Derive the Henderson-Hasselbalch equation and mention its significance.
Answer
575.1k+ views
Hint: The Henderson-Hasselbalch equation was independently developed by the Swedish physiologist K.A. Hasselbalch and the American biological chemist L.J. Henderson to determine the pH of the bicarbonate buffer system of the blood.
The Henderson-Hasselbalch equation establishes a relationship between the pH of the solution containing a mixture of two components to the acid dissociation constant, \[{\text{p}}{{\text{K}}_{\text{a}}}\] and the concentration of involved chemical species.
Complete step by step answer:
We will now try to derive the Henderson-Hasselbalch equation in a step-by-step manner to understand it in a broader perspective:
Let us consider a weak acid HA, having the following ionic equilibrium:
${\text{HA}} \rightleftharpoons {{\text{H}}^{\text{ + }}}{\text{ + }}{{\text{A}}^{\text{ - }}}$ ……………………1.)
According the above reaction the acid dissociation constant of HA will be,
${{\text{K}}_{\text{a}}}{\text{ = }}{{{\text{[}}{{\text{H}}^{\text{ + }}}{\text{][}}{{\text{A}}^{\text{ - }}}{\text{]}}}}{{{\text{[HA]}}}}$ ……………………2.)
Rearranging the above equation, we get,
${\text{[}}{{\text{H}}^{\text{ + }}}{\text{] = }}{{\text{K}}_{\text{a}}}{\text{ \times }}{{{\text{[HA]}}}}{{{\text{[}}{{\text{A}}^{\text{ - }}}{\text{]}}}}$ …………………..3.)
Taking negative logarithm of the equation 3.),
${\text{ - log[}}{{\text{H}}^{\text{ + }}}{\text{] = - log}}{{\text{K}}_{\text{a}}}{\text{ - log}} {{{\text{[HA]}}}}{{{\text{[}}{{\text{A}}^{\text{ - }}}{\text{]}}}}$
Since pH= -log ${\text{[}}{{\text{H}}^{\text{ + }}}{\text{]}}$, the above equation can now be written as,
${\text{pH = p}}{{\text{K}}_{\text{a}}}{\text{ - log}} {{{\text{[HA]}}}}{{{\text{[}}{{\text{A}}^{\text{ + }}}{\text{]}}}}$ Or
${\text{pH = p}}{{\text{K}}_{\text{a}}}{\text{ + log}} {{{\text{[}}{{\text{A}}^{\text{ - }}}{\text{]}}}}{{{\text{[HA]}}}}$ ………………………4.)
In the above equation ${\text{[}}{{\text{A}}^{\text{ - }}}{\text{]}}$ is a proton acceptor and [HA] is a proton donor so it can be written in the form of,
${\text{pH = p}}{{\text{K}}_{\text{a}}}{\text{ + log}} {{{\text{(protonacceptor)}}}}{{{\text{(protondonar)}}}}$ …………….5.)
The equation 4.) And 5.) Is known as Henderson-Hasselbalch equation.
Significance of this equation:
The Henderson-Hasselbalch equation can be used to calculate the pH of a buffer solution using the initial concentration of the weak acid and the salt and ${{\text{K}}_{\text{a}}}$.
And if the pH of the solution is given together with other information of initial concentration of weak acid its salt it can be used to calculate the acid dissociation constant of the weak acid.
The equation can also be used to determine the amount of acid and the conjugate base (it's salt) required to prepare a buffer of a particular pH.
This equation considered the backbone of acid-base physiology.
Note:A buffer solution can be defined as a mixture of a weak acid, its conjugate base or a base and its conjugate acid (in a particular ratio for the desired pH). The pH of a buffer solution changes very little when a small amount of strong acid or base is added to it. Buffer solutions are of two types:
Acidic Buffer: It has a pH of less than 7 and made up of weak acid and its salt (often a sodium salt). E.g., a mixture of ethanoic acid and sodium ethanoate in an aqueous medium
Alkaline buffer: It has a pH of more than 7 and made up of a weak base and its salt. For example, a mixture of ammonium hydroxide and ammonium chloride.
The Henderson-Hasselbalch equation establishes a relationship between the pH of the solution containing a mixture of two components to the acid dissociation constant, \[{\text{p}}{{\text{K}}_{\text{a}}}\] and the concentration of involved chemical species.
Complete step by step answer:
We will now try to derive the Henderson-Hasselbalch equation in a step-by-step manner to understand it in a broader perspective:
Let us consider a weak acid HA, having the following ionic equilibrium:
${\text{HA}} \rightleftharpoons {{\text{H}}^{\text{ + }}}{\text{ + }}{{\text{A}}^{\text{ - }}}$ ……………………1.)
According the above reaction the acid dissociation constant of HA will be,
${{\text{K}}_{\text{a}}}{\text{ = }}{{{\text{[}}{{\text{H}}^{\text{ + }}}{\text{][}}{{\text{A}}^{\text{ - }}}{\text{]}}}}{{{\text{[HA]}}}}$ ……………………2.)
Rearranging the above equation, we get,
${\text{[}}{{\text{H}}^{\text{ + }}}{\text{] = }}{{\text{K}}_{\text{a}}}{\text{ \times }}{{{\text{[HA]}}}}{{{\text{[}}{{\text{A}}^{\text{ - }}}{\text{]}}}}$ …………………..3.)
Taking negative logarithm of the equation 3.),
${\text{ - log[}}{{\text{H}}^{\text{ + }}}{\text{] = - log}}{{\text{K}}_{\text{a}}}{\text{ - log}} {{{\text{[HA]}}}}{{{\text{[}}{{\text{A}}^{\text{ - }}}{\text{]}}}}$
Since pH= -log ${\text{[}}{{\text{H}}^{\text{ + }}}{\text{]}}$, the above equation can now be written as,
${\text{pH = p}}{{\text{K}}_{\text{a}}}{\text{ - log}} {{{\text{[HA]}}}}{{{\text{[}}{{\text{A}}^{\text{ + }}}{\text{]}}}}$ Or
${\text{pH = p}}{{\text{K}}_{\text{a}}}{\text{ + log}} {{{\text{[}}{{\text{A}}^{\text{ - }}}{\text{]}}}}{{{\text{[HA]}}}}$ ………………………4.)
In the above equation ${\text{[}}{{\text{A}}^{\text{ - }}}{\text{]}}$ is a proton acceptor and [HA] is a proton donor so it can be written in the form of,
${\text{pH = p}}{{\text{K}}_{\text{a}}}{\text{ + log}} {{{\text{(protonacceptor)}}}}{{{\text{(protondonar)}}}}$ …………….5.)
The equation 4.) And 5.) Is known as Henderson-Hasselbalch equation.
Significance of this equation:
The Henderson-Hasselbalch equation can be used to calculate the pH of a buffer solution using the initial concentration of the weak acid and the salt and ${{\text{K}}_{\text{a}}}$.
And if the pH of the solution is given together with other information of initial concentration of weak acid its salt it can be used to calculate the acid dissociation constant of the weak acid.
The equation can also be used to determine the amount of acid and the conjugate base (it's salt) required to prepare a buffer of a particular pH.
This equation considered the backbone of acid-base physiology.
Note:A buffer solution can be defined as a mixture of a weak acid, its conjugate base or a base and its conjugate acid (in a particular ratio for the desired pH). The pH of a buffer solution changes very little when a small amount of strong acid or base is added to it. Buffer solutions are of two types:
Acidic Buffer: It has a pH of less than 7 and made up of weak acid and its salt (often a sodium salt). E.g., a mixture of ethanoic acid and sodium ethanoate in an aqueous medium
Alkaline buffer: It has a pH of more than 7 and made up of a weak base and its salt. For example, a mixture of ammonium hydroxide and ammonium chloride.
Recently Updated Pages
The number of solutions in x in 02pi for which sqrt class 12 maths CBSE

Write any two methods of preparation of phenol Give class 12 chemistry CBSE

Differentiate between action potential and resting class 12 biology CBSE

Two plane mirrors arranged at right angles to each class 12 physics CBSE

Which of the following molecules is are chiral A I class 12 chemistry CBSE

Name different types of neurons and give one function class 12 biology CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

What is 1s 2s 2p 3s 3p class 11 chemistry CBSE

Discuss the various forms of bacteria class 11 biology CBSE

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

An example of chemosynthetic bacteria is A E coli B class 11 biology CBSE

