
What is the derivative of ${\sin ^2}\left( {5x} \right)$?
Answer
477.9k+ views
Hint:In the given problem, we are required to differentiate ${\sin ^2}\left( {5x} \right)$ with respect to x. The given function is a composite function, so we will have to apply the chain rule of differentiation in the process of differentiation. So, differentiation of ${\sin ^2}\left( {5x} \right)$ with respect to x will be done layer by layer. Also the derivative of $\sin x$with respect to x must be remembered.
Complete step by step solution:
So, Derivative of ${\sin ^2}\left( {5x} \right)$ with respect to $x$can be calculated as $\dfrac{d}{{dx}}\left( {{{\sin }^2}\left( {5x} \right)} \right)$ .
Now, $\dfrac{d}{{dx}}\left( {{{\sin }^2}\left( {5x} \right)} \right)$
Now, Let us assume $u = \sin 5x$. So substituting $\sin 5x$ as $u$, we get,
$ = $$\dfrac{d}{{dx}}\left( {{u^2}} \right)$
Now, we know the power rule of differentiation as $\dfrac{{d\left( {{x^n}} \right)}}{{dx}} = n{x^{n - 1}}$. So, we get,
$ = 2u\left( {\dfrac{{du}}{{dx}}} \right)$
Now, putting back $u$as $\sin 5x$, we get,
$ = 2\sin 5x\left( {\dfrac{{d\left( {\sin 5x} \right)}}{{dx}}} \right)$ because \[\dfrac{{du}}{{dx}} = \dfrac{{d\left( {\sin 5x} \right)}}{{dx}}\]
Now, taking $t = 5x$. We get,
$ = 2\sin 5x\left( {\dfrac{{d\left( {\sin t} \right)}}{{dx}}} \right)$
We know that derivative of sine is equal to cosine. So, we get,
$ = 2\sin 5x\left[ {\cos t \times \dfrac{{dt}}{{dx}}} \right]$
Now, putting back the value of t in the equation, we get,
$ = 2\sin 5x\left[ {\cos \left( {5x} \right) \times \dfrac{{d\left( {5x} \right)}}{{dx}}} \right]$
Using the power rule of differentiation again, we get,
$ = 2\sin 5x\left[ {\cos \left( {5x} \right) \times 5} \right]$
Simplifying the expression, we get,
$ = 10\sin 5x\cos 5x$
Now, we know the double angle formula for sine as $\sin 2x = 2\sin x\cos x$. Hence, we get,
$ = 5\sin \left( {10x} \right)$
So, the derivative of ${\sin ^2}\left( {5x} \right)$ with respect to $x$ is \[\sin 10x\].
Note:
The chain rule of differentiation involves differentiating a composite by introducing new unknowns to ease the process and examine the behaviour of function layer by layer. Answer to the given problem can also be reported as $10\sin 5x\cos 5x$ before applying the double angle formula for sine function, but it is better to provide the final answer in the condensed form.
Complete step by step solution:
So, Derivative of ${\sin ^2}\left( {5x} \right)$ with respect to $x$can be calculated as $\dfrac{d}{{dx}}\left( {{{\sin }^2}\left( {5x} \right)} \right)$ .
Now, $\dfrac{d}{{dx}}\left( {{{\sin }^2}\left( {5x} \right)} \right)$
Now, Let us assume $u = \sin 5x$. So substituting $\sin 5x$ as $u$, we get,
$ = $$\dfrac{d}{{dx}}\left( {{u^2}} \right)$
Now, we know the power rule of differentiation as $\dfrac{{d\left( {{x^n}} \right)}}{{dx}} = n{x^{n - 1}}$. So, we get,
$ = 2u\left( {\dfrac{{du}}{{dx}}} \right)$
Now, putting back $u$as $\sin 5x$, we get,
$ = 2\sin 5x\left( {\dfrac{{d\left( {\sin 5x} \right)}}{{dx}}} \right)$ because \[\dfrac{{du}}{{dx}} = \dfrac{{d\left( {\sin 5x} \right)}}{{dx}}\]
Now, taking $t = 5x$. We get,
$ = 2\sin 5x\left( {\dfrac{{d\left( {\sin t} \right)}}{{dx}}} \right)$
We know that derivative of sine is equal to cosine. So, we get,
$ = 2\sin 5x\left[ {\cos t \times \dfrac{{dt}}{{dx}}} \right]$
Now, putting back the value of t in the equation, we get,
$ = 2\sin 5x\left[ {\cos \left( {5x} \right) \times \dfrac{{d\left( {5x} \right)}}{{dx}}} \right]$
Using the power rule of differentiation again, we get,
$ = 2\sin 5x\left[ {\cos \left( {5x} \right) \times 5} \right]$
Simplifying the expression, we get,
$ = 10\sin 5x\cos 5x$
Now, we know the double angle formula for sine as $\sin 2x = 2\sin x\cos x$. Hence, we get,
$ = 5\sin \left( {10x} \right)$
So, the derivative of ${\sin ^2}\left( {5x} \right)$ with respect to $x$ is \[\sin 10x\].
Note:
The chain rule of differentiation involves differentiating a composite by introducing new unknowns to ease the process and examine the behaviour of function layer by layer. Answer to the given problem can also be reported as $10\sin 5x\cos 5x$ before applying the double angle formula for sine function, but it is better to provide the final answer in the condensed form.
Recently Updated Pages
Why are manures considered better than fertilizers class 11 biology CBSE

Find the coordinates of the midpoint of the line segment class 11 maths CBSE

Distinguish between static friction limiting friction class 11 physics CBSE

The Chairman of the constituent Assembly was A Jawaharlal class 11 social science CBSE

The first National Commission on Labour NCL submitted class 11 social science CBSE

Number of all subshell of n + l 7 is A 4 B 5 C 6 D class 11 chemistry CBSE

Trending doubts
Differentiate between an exothermic and an endothermic class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

State the laws of reflection of light

