Question

What is the density of a block of marble that occupies \[310c{{m}^{3}}\] and has a mass of \[853\text{ }g\] ?

Answer 1

Hint: Use the given information in question and put it in the formula of density which is:
\[density(\rho )=\dfrac{mass\text{ of given substance(m)}}{volume\text{ of given substance(V)}}\]

Complete answer:
Now it is given in question that the mass of marble block is \[853\text{ }g\] that means the value of m = \[853\text{ }g\] and the volume occupied by the marble block is given which is \[310c{{m}^{3}}\] that means the value of V = \[310c{{m}^{3}}\] , now putting the value of m and V in the formula of density which is
\[density(\rho )=\dfrac{mass\text{ of given substance(m)}}{volume\text{ of given substance(V)}}\]
Putting the values we will get our answer:
\[\rho =\dfrac{853}{310}g\text{ c}{{\text{m}}^{-3}}\]
\[\rho =2.751g\text{ c}{{\text{m}}^{-3}}\]
Hence, it is our answer.

Note:
The unit of density depends on the fact that in which unit the mass and the volume is given so keep the unit of mass and volume in check.