Question

What is the degree of the monomial $3{x^2}{y^3}?$

Answer 1

Hint: As we know that a monomial is a special kind of polynomial which is an algebraic expression having only one single term which is non zero. In this question we have to find the degree of the monomial. The degree of the monomial is defined as the sum of all the exponents of the variables .

Complete step-by-step answer:
We have a monomial $3{x^2}{y^3}$.
Since we can see that the exponent of the first variable ${x^2}$ is $2$ and the exponent of the second variable ${y^3}$ is $3$.
Now we add the exponents of the variables i.e. $3 + 2 = 5$.
Hence the degree of the monomial $3{x^2}{y^3}$ is $5$.
So, the correct answer is “5”.

Note: we should note that if any variable has no exponent i.e. no power written on its top, then its power is $1$ and the degree of the non zero constant is zero. In order to solve this type of question, the key is to know what it means by a degree of a monomial. While calculating the degree we do not take the scalar value before the variable into consideration, only the power of the variable matters.