
What is the degree of hardness of a sample of water containing 24 mg of $MgS{O_4}$ (molecular mass 120) per kg of water?
A.10 ppm
B.15 ppm
C.20 ppm
D.25 ppm
Answer
513k+ views
Hint:Here, the hardness of water is permanent. The hardness of water is calculated in terms of the weight of $CaC{O_3}$. 1ppm = 1mg/L. The molecular weight of $CaC{O_3}$ = 100. The degree of hardness is expressed as parts per million (ppm).
Complete step by step answer:
The hardness of water is of two types: permanent and temporary.
Temporary hardness is due to the presence of magnesium and calcium hydrogen carbonates.
Presence of insoluble salts like $MgS{O_4}$ causes permanent hardness of the water.
The amount of hardness causing substances in a certain volume of water measures the degree of hardness.
The hardness of water is always calculated in terms of calcium carbonate ($CaC{O_3}$). However, it is never responsible for causing hardness as it is insoluble in water.
.
As mentioned, the degree of hardness is expressed as parts per million (ppm) and thus may be defined as the number of parts by weight of $CaC{O_3}$ (equivalent to Mg salts) present in a million (${10^6}$) parts by weight of water.
It is given that 1 kg of water contains 24 mg of $MgS{O_4}$.
i.e., 1000 g of water contains 24 mg of $MgS{O_4}$
therefore, 1 million grams of water (${10^6}$g ) contains 24 mg $ \times $ 1000 = 24 g of $MgS{O_4}$
1 mole of $MgS{O_4}$ = 1 mole of $CaC{O_3}$
The molecular weight of $MgS{O_4}$ = 120g/mol and $CaC{O_3}$= 100g/mol
120 g of $MgS{O_4}$ = 100 g of$CaC{O_3}$
Therefore, the equivalent amount of $CaC{O_3}$ for 24 mg of $MgS{O_4}$ = 24 $ \times $ 100 /120 = 20 ppm.
Hence, the degree of hardness of water is 20 ppm.
The correct answer is (C) 20 ppm.
Note: Here, 1 ppm = 1 part of $CaC{O_3}$ in ${10^6}$ parts of water
-$CaC{O_3}$ is chosen as the standard for calculating the hardness of water because its molecular weight is 100 and this makes it easier to do the calculations.
-Calcium carbonate is not responsible for the hardness of the water.
-Another method used to detect the hardness of water is by performing complexometric titrations using EDTA.
Complete step by step answer:
The hardness of water is of two types: permanent and temporary.
Temporary hardness is due to the presence of magnesium and calcium hydrogen carbonates.
Presence of insoluble salts like $MgS{O_4}$ causes permanent hardness of the water.
The amount of hardness causing substances in a certain volume of water measures the degree of hardness.
The hardness of water is always calculated in terms of calcium carbonate ($CaC{O_3}$). However, it is never responsible for causing hardness as it is insoluble in water.
.
As mentioned, the degree of hardness is expressed as parts per million (ppm) and thus may be defined as the number of parts by weight of $CaC{O_3}$ (equivalent to Mg salts) present in a million (${10^6}$) parts by weight of water.
It is given that 1 kg of water contains 24 mg of $MgS{O_4}$.
i.e., 1000 g of water contains 24 mg of $MgS{O_4}$
therefore, 1 million grams of water (${10^6}$g ) contains 24 mg $ \times $ 1000 = 24 g of $MgS{O_4}$
1 mole of $MgS{O_4}$ = 1 mole of $CaC{O_3}$
The molecular weight of $MgS{O_4}$ = 120g/mol and $CaC{O_3}$= 100g/mol
120 g of $MgS{O_4}$ = 100 g of$CaC{O_3}$
Therefore, the equivalent amount of $CaC{O_3}$ for 24 mg of $MgS{O_4}$ = 24 $ \times $ 100 /120 = 20 ppm.
Hence, the degree of hardness of water is 20 ppm.
The correct answer is (C) 20 ppm.
Note: Here, 1 ppm = 1 part of $CaC{O_3}$ in ${10^6}$ parts of water
-$CaC{O_3}$ is chosen as the standard for calculating the hardness of water because its molecular weight is 100 and this makes it easier to do the calculations.
-Calcium carbonate is not responsible for the hardness of the water.
-Another method used to detect the hardness of water is by performing complexometric titrations using EDTA.
Recently Updated Pages
Master Class 11 Business Studies: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Trending doubts
Differentiate between an exothermic and an endothermic class 11 chemistry CBSE

10 examples of friction in our daily life

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

State the laws of reflection of light

Explain zero factorial class 11 maths CBSE

