Define the following and state their numerical values in si unit system:
A) specific latent heat of fusion of ice
B) specific latent heat of vaporization of system
Answer
606.6k+ views
Hint: The specific latent heat of fusion of ice is the heat energy required to change one kilo of ice from solid to liquid state. Specific latent heat of fusion of vaporization is the heat required to change one kilo of water in the liquid state to a gaseous state.
Formulas used:
$\begin{align}
& {{L}_{f}}=\dfrac{q}{m} \\
& \\
\end{align}$
Complete step-by-step solution:
The amount of heat energy released or absorbed when a solid changes to liquid at atmospheric pressure at its melting point is known as the latent heat of fusion. For the material ice, it is defined as the amount of heat required to change one gram of ice to water at the same ${{0}^{0}}C$. The value of latent heat of fusion of ice is $3.36\times {{10}^{5}}JK{{g}^{-1}}$ in S.I. unit of system.
The specific latent heat of vaporization of the system is the heat energy needed to change one kilogram of the material in its liquid state at its boiling point to one kilogram of the material in its gaseous state. For water, it is defined as the heat energy released when one kilogram of water changes to one kilogram of vapor. It is called the same when the reverse process occurs.
The value of the specific latent heat of fusion of water is $2,260kJK{{g}^{-1}}$ in the SI unit of the system.
Additional information: In the cgs unit system, the latent heat of vaporization of water is $40.8kJmo{{l}^{-1}}$. Similarly, the latent heat of fusion of ice in the cgs system is $80ca{{\lg }^{-1}}$.
Note: While calculating the latent heat of fusion of ice experimentally, we’ve to stir the water thoroughly as the mixture will uniformly get heated, if not so, the temperature will not be the same value and we will make mistakes. The latent heat of fusion is the conversion of ice to water whereas the latent heat of vaporization is the conversion of water to water vapor.
Formulas used:
$\begin{align}
& {{L}_{f}}=\dfrac{q}{m} \\
& \\
\end{align}$
Complete step-by-step solution:
The amount of heat energy released or absorbed when a solid changes to liquid at atmospheric pressure at its melting point is known as the latent heat of fusion. For the material ice, it is defined as the amount of heat required to change one gram of ice to water at the same ${{0}^{0}}C$. The value of latent heat of fusion of ice is $3.36\times {{10}^{5}}JK{{g}^{-1}}$ in S.I. unit of system.
The specific latent heat of vaporization of the system is the heat energy needed to change one kilogram of the material in its liquid state at its boiling point to one kilogram of the material in its gaseous state. For water, it is defined as the heat energy released when one kilogram of water changes to one kilogram of vapor. It is called the same when the reverse process occurs.
The value of the specific latent heat of fusion of water is $2,260kJK{{g}^{-1}}$ in the SI unit of the system.
Additional information: In the cgs unit system, the latent heat of vaporization of water is $40.8kJmo{{l}^{-1}}$. Similarly, the latent heat of fusion of ice in the cgs system is $80ca{{\lg }^{-1}}$.
Note: While calculating the latent heat of fusion of ice experimentally, we’ve to stir the water thoroughly as the mixture will uniformly get heated, if not so, the temperature will not be the same value and we will make mistakes. The latent heat of fusion is the conversion of ice to water whereas the latent heat of vaporization is the conversion of water to water vapor.
Recently Updated Pages
Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Master Class 11 Maths: Engaging Questions & Answers for Success

Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Computer Science: Engaging Questions & Answers for Success

Master Class 11 Chemistry: Engaging Questions & Answers for Success

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

There are 720 permutations of the digits 1 2 3 4 5 class 11 maths CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

State and prove Bernoullis theorem class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

Which among the following are examples of coming together class 11 social science CBSE

