Question

Define one coulomb charge according to coulomb's law.

Answer 1

Hint :According to coulomb’s law, we have to take into consideration the electric charge of a circuit and the first law, second law, the third law of coulomb. And also, we have to take into consideration the time taken by the current to flow.

Complete Step By Step Answer:
The electric charge that flows through any circuit of any cross section can be explained as the product of the current passing through the cross section of that circuit and the time taken by it. The SI unit of the electric charge is coulomb and it is denoted as $ C $ . The formula to deter mine the electric charge is given as;
  $ Q = I \times t $
Where,
 $ Q $ denotes the charge,
 $ I $ denotes the current,
 $ t $ time taken.
Coulomb’s law can be explained that the opposite charges will constantly attract in contrast the like charges repel each other, in which the force will be proportional in straight with the product of charges and inversely proportional to the square of their distance.
 $ F = K\left( {\dfrac{{{Q_1} \times {Q_2}}}{{{d^2}}}} \right) $
Where,
 $ F $ denotes the force between the charge,
 $ K $ denotes as the constant,
 $ {Q_1} $ denotes one of the charges,
 $ {Q_2} $ denotes the next charge,
 $ d $ denotes the distance between them.
The amount of charge which is kept at a distance of $ 1\,\,m $ in the air or the vacuum from an identical and alike charges, which encounter a repulsive force of $ 9 \times {10^9}\,\,N $ is known as the one coulomb of charge according to coulomb’s law.

Note :
The SI The unit for the coulomb's law is $ {C^{2\,}}\,{N^{ - 1}}\,{m^{ - 2}} $ . The coulomb's constant is also known as the electric permittivity constant, which is denoted as the $ {\varepsilon _o} $ . The charge of the circuit is directly proportional to the current and the time taken.