
Define back bonding and explain its effects on acid strength.
Answer
461.4k+ views
Hint: A bond is a force existing between atoms in a molecule that holds the atoms together. Back bonding makes the compound stable as on its completion the octet rule is satisfied. Also a compound with back bonding has $\pi $-bonding character since it results after formation of sigma bond.
Complete answer:
Back bonding is the bonding of $\pi $-conjugated ligands to a transition metal which involves a synergic process with donation of electrons from the filled $\pi $-orbital or lone pair orbital of the ligand into an empty orbital of the metal (donor-acceptor bond) together with the release (back donation) of electrons from the d orbital of the metal into empty ${{\pi }^{*}}$antibonding orbital of the ligand.
Back bonding decreases down the halogen group.
$$F > Cl > Br > I
As for acid strength i.e.$B{{F}_{3}},BB{{r}_{3}}$ etc are lewis acids because the central atom is short of an electron pair.
So when the back bonding is effective, the shortage of electrons is compensated and the lewis acid character decreases.
Hence acid strength decreases down the halogen group due to the effect of back bonding.
Note:
Back bonding is only effective when the size of valence shell matches. For example in $B{{F}_{3}}$ both boron and fluorine have their valence electrons in 2p but in $BB{{r}_{3}}$, lone pair electrons are in 4p while valence electrons of Boron are in 2p, so the size does not match. So back bonding decreases down the halogen group.
Complete answer:
Back bonding is the bonding of $\pi $-conjugated ligands to a transition metal which involves a synergic process with donation of electrons from the filled $\pi $-orbital or lone pair orbital of the ligand into an empty orbital of the metal (donor-acceptor bond) together with the release (back donation) of electrons from the d orbital of the metal into empty ${{\pi }^{*}}$antibonding orbital of the ligand.
Back bonding decreases down the halogen group.
$$F > Cl > Br > I
As for acid strength i.e.$B{{F}_{3}},BB{{r}_{3}}$ etc are lewis acids because the central atom is short of an electron pair.
So when the back bonding is effective, the shortage of electrons is compensated and the lewis acid character decreases.
Hence acid strength decreases down the halogen group due to the effect of back bonding.
Note:
Back bonding is only effective when the size of valence shell matches. For example in $B{{F}_{3}}$ both boron and fluorine have their valence electrons in 2p but in $BB{{r}_{3}}$, lone pair electrons are in 4p while valence electrons of Boron are in 2p, so the size does not match. So back bonding decreases down the halogen group.
Recently Updated Pages
Master Class 11 Economics: Engaging Questions & Answers for Success

Master Class 11 Accountancy: Engaging Questions & Answers for Success

Master Class 11 English: Engaging Questions & Answers for Success

Master Class 11 Social Science: Engaging Questions & Answers for Success

Master Class 11 Biology: Engaging Questions & Answers for Success

Master Class 11 Physics: Engaging Questions & Answers for Success

Trending doubts
1 ton equals to A 100 kg B 1000 kg C 10 kg D 10000 class 11 physics CBSE

Difference Between Prokaryotic Cells and Eukaryotic Cells

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

1 Quintal is equal to a 110 kg b 10 kg c 100kg d 1000 class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

Explain zero factorial class 11 maths CBSE
