
Define a function as corresponding to two sets.
Answer
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Hint: We have to know the set theory and the definition of Relation of sets to define a function. A function is a special relation between two sets.
Complete step by step solution:
A function is a special relation between the elements of two sets such that every element of the first set will have a unique image in the second set. So, every element of set A will have one and only one image in set B.
For example, Let A and B be two sets containing elements $\left\{ {1,2,3} \right\}$and $\left\{ {1,2,3,4,5,6,7,8,9,10} \right\}$respectively. Let us consider a relation $f$from set A to B , defined as $f:A \to B$ such that every element a of A, has one and only one image $f(a)$in B defined as $f(a) = 3a\forall a \in A$. Then the elements of the function will be:
$ f(1) = 1 \times 3 = 3 \\
f(2) = 2 \times 3 = 6 \\
f\left( 3 \right) = 3 \times 3 = 9 \\ $
Which belong to B.
That is, every element of A has one and only one image in B. Hence, $f$ is a function
However not every image in B has a pre- image in A.
The set A is called the Domain of the function $f$ while the set B becomes the Range of the function $f$.
Note: Function is not to be confused with Relation. Apart from equal functions there are other types of functions also. Let us consider two sets A and B. A one-to-one function is one where every element belonging to a set A, that has exactly one unique image in set B. An onto function is one where every element belonging to set B has at least one preimage in the set A. A function which is both one-to-one and onto, is called an injective function. If either of the characteristics is missing, the function will not be an injective function.
Complete step by step solution:
A function is a special relation between the elements of two sets such that every element of the first set will have a unique image in the second set. So, every element of set A will have one and only one image in set B.
For example, Let A and B be two sets containing elements $\left\{ {1,2,3} \right\}$and $\left\{ {1,2,3,4,5,6,7,8,9,10} \right\}$respectively. Let us consider a relation $f$from set A to B , defined as $f:A \to B$ such that every element a of A, has one and only one image $f(a)$in B defined as $f(a) = 3a\forall a \in A$. Then the elements of the function will be:
$ f(1) = 1 \times 3 = 3 \\
f(2) = 2 \times 3 = 6 \\
f\left( 3 \right) = 3 \times 3 = 9 \\ $
Which belong to B.
That is, every element of A has one and only one image in B. Hence, $f$ is a function
However not every image in B has a pre- image in A.
The set A is called the Domain of the function $f$ while the set B becomes the Range of the function $f$.
Note: Function is not to be confused with Relation. Apart from equal functions there are other types of functions also. Let us consider two sets A and B. A one-to-one function is one where every element belonging to a set A, that has exactly one unique image in set B. An onto function is one where every element belonging to set B has at least one preimage in the set A. A function which is both one-to-one and onto, is called an injective function. If either of the characteristics is missing, the function will not be an injective function.
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